Proving Analytic Function Convergence Using Constant Sum of Squares

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Homework Help Overview

The discussion revolves around proving that a set of analytic functions, constrained by a constant sum of their squared magnitudes, must all be constant functions. The subject area involves complex analysis, specifically the properties of analytic and harmonic functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between analytic functions and harmonic functions, questioning how to apply derivatives to the given equation. There is discussion about differentiating the equation with respect to real and imaginary components.

Discussion Status

The conversation is ongoing, with participants attempting to clarify the definitions and properties of harmonic functions in relation to the problem. Some guidance has been offered regarding the differentiation process, but no consensus or resolution has been reached yet.

Contextual Notes

Participants are navigating the complexities of the problem, including the need to express the functions in terms of their real and imaginary parts and the implications of the constant sum of squares condition. There is also mention of potential missing information regarding the specific forms of the functions involved.

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Homework Statement


Let f1(z),... fn(z) n >1 be analytic functions on a domain D such that |f1 (z)|2 +...+|fn(z)|2 = k (k is constant). Verify that all the functions must reduce to constants


Homework Equations





The Attempt at a Solution


Having the hardest time proving this, not sure where to being...
 
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What tools do you have to work with? I can probably think of a few ways to do this. Do you know what a harmonic function is?
 
You mean harmonic function in terms of being analytic, or something else?

Also i was given the hit that |fk(z)|2 (|f1(z)|2Delta f1(z)|2)
 
Well a harmonic function can be defined independently of analytic function theory, but yes the real and complex parts of an analytic function are harmonic, i.e., they satisfy http://en.wikipedia.org/wiki/Laplace's_equation#Laplace_equation_in_two_dimensions".

The original equation can be written in terms of the real and complex parts of each f_i (i = 1, ..., k). Differentiating the original equation twice with respect to x gives a new equation, call it (1). Differentiating the original equation twice with respect to y (use symmetry here), we get another equation (2). What happens when you add equations (1) and (2)?
 
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So would (1) be [tex]\partial[/tex]x (|f1(z)|2 +...|fk(z)|2?
 
Well no, you should have two x's in the subscript, but never mind that. Writing it that way doesn't do anything since you didn't actually take derivatives. Put [itex]f_j = u_j + iv_j[/itex], (j = 1, ..., k) and write [itex]|f_1(z)|^2 +...|f_k(z)|^2[/itex] in terms of the real and complex parts of each [itex]f_j[/itex]. Then take two partial derivatives with respect to x and call that (1).
 
Ok so i got |f1(z)|2 = f1(z)f1(z(bar)) = (x1+iy1)(x1-iy1) + ... + (xn+iyn)(xn-iyn)

then separated it into real and imaginare parts
Re{(x1)(x1) + ...+ (xn)(xn)
partial x = 2(x1)+ 2(x2) +...+ 2(xn)
or did you mean partial x = 2(x1)(dx/dz)+ 2(x2)(dx/dz) +...+ 2(xn)(dx/dz)? or do i need to keep it (x+iy)(x-iy) and then do the partial?
 

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