Proving Boundary of Union is Subset of Union of Boundaries

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Homework Help Overview

The discussion revolves around proving that the boundary of the union of two sets is a subset of the union of the boundaries of those sets, specifically showing that B(X ∪ Y) ⊆ B(X) ∪ B(Y).

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between boundaries and closures, with one participant initially attempting to use set algebra involving closure. Another participant questions the necessity of closure in the proof and suggests focusing on boundary points directly.

Discussion Status

The discussion has evolved with participants sharing their understanding and clarifying concepts. One participant has resolved their confusion regarding the use of closure versus complement, indicating progress in their reasoning.

Contextual Notes

One participant expressed confusion about the notation used, mistaking closure for complement, which highlights the importance of clear definitions in set theory discussions.

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Homework Statement



I'm trying to prove that the boundary of the union of two sets is a subset of the union of the boundaries of the two sets. i.e. Show that B(X u Y) c= B(X) u B(Y).

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The Attempt at a Solution



Since I didn't know what to do here, I used the identity A c= B <==> cl(B) c= cl(A), and then a lot of set algebra to prove it. Given how simple the statement looks, I'm wondering if there is an easier way. Thanks.
 
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I don't see any need to deal with the closure. If x is a member of B(X \cup Y), what does that tell you about x? Use that to prove it must be a boundary point of X or a boundary point of Y.
 
Actually, didn't know what closure is, so confused the cl symbol I've seen, with complement. So, yea, when I wrote cl I meant complement.

O let me try this. If x in B(X u Y) then for all r>0 the r-neighbourhood of x contains at least some point p in X u Y and another point q in C(X u Y) , (C stands for complement). But now I'm having difficulty with the case where p in X but q in C(Y). This gives the possibility that x is in none of the boundaries of the sets. But if you say that x must be in the boundaries of the sets, then there is no need to solve the problem.
 
Im good, got it, just had to use C(X u Y) = C(X) n C(Y), so now it is clear what hapens to q. thank you.
 

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