Proving C1 Continuity of a Person's Path in a 2D Environment

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The discussion centers on proving the C1 continuity of a person's path in a 2D environment based on their motion influenced by a force function f(t). It is established that if f(t) is finite, the resulting velocity will also be continuous, as velocity is derived from the integral of acceleration, which is linked to the force applied. The continuity of the path is maintained as long as the discontinuities in f(t) are limited to a set of measure zero, meaning they can be countably infinite and consist of step discontinuities. This ensures that the integral of f(t)/m remains continuous. Therefore, under these conditions, the motion can be proven to be C1 continuous.
12monkey
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Dear all,
I would appreciate if you could help me with the following problem:
A person is standing still on a 2D environment and let's assume that its initial position Xo is given. The person is moving by applying a force function over time say f(t). As a result, using numerical integration we can determine the person's acceleration, velocity and position at any time step.
My question is how we can prove that the resulting path/motion is or is not C1 continuous?
 
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12monkey said:
Dear all,
I would appreciate if you could help me with the following problem:
A person is standing still on a 2D environment and let's assume that its initial position Xo is given. The person is moving by applying a force function over time say f(t). As a result, using numerical integration we can determine the person's acceleration, velocity and position at any time step.
My question is how we can prove that the resulting path/motion is or is not C1 continuous?
As long as f(t) is finite, the resultant velocity will be continuous.
 
F= ma and v is the integral of a. That is, v is the integral of f(t)/m. As long as the set of points at which the function f(t) is discontinuous has measure 0 (no more that countably infinite is sufficient) and those discontinuities are step discontinuities (and if, as mathman says, the function is finite that is true) then its integral is continuous.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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