- #1

Dustinsfl

- 2,281

- 5

Let [itex]\epsilon>0[/itex]. Then [itex]\exists N_1,N_2\in\mathbb{N}, \ n\geq N_1,N_2[/itex]

[tex]|a_n-A|<\frac{\epsilon}{2}[/tex]

And let [itex]\{a_nb_n\}\to AB[/itex]

So, [itex]|a_nb_n-AB|<\epsilon[/itex]

I don't know how to show b_n is < epsilon.