Proving convergence of infinite series

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SUMMARY

The series \(\sum \frac{(-1)^{n}}{n+n^{2}}\) converges as \(n \to \infty\). This conclusion is reached by applying the absolute convergence test, where it is established that \(\sum \left|\frac{(-1)^{n}}{n+n^{2}}\right|\) converges. The comparison test is utilized, showing that \(\frac{1}{n+n^{2}} < \sum \frac{1}{n^{2}}\), and since \(\sum \frac{1}{n^{2}}\) converges, it follows that \(\sum \left|\frac{(-1)^{n}}{n+n^{2}}\right|\) converges. Therefore, the original series converges by the absolute convergence test.

PREREQUISITES
  • Understanding of series convergence tests, specifically the absolute convergence test.
  • Familiarity with the comparison test in series analysis.
  • Knowledge of the convergence of the p-series, particularly \(\sum \frac{1}{n^{2}}\).
  • Basic algebraic manipulation of series terms.
NEXT STEPS
  • Study the details of the absolute convergence test for series.
  • Learn more about the comparison test and its applications in series convergence.
  • Explore the properties of p-series and their convergence criteria.
  • Investigate other convergence tests such as the ratio test and root test.
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators teaching these concepts in mathematics courses.

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Homework Statement



[tex]\sum \frac{(-1)^{n}}{n+n^{2}}[/tex]

Does this series converge as n -> infinity?

Homework Equations





The Attempt at a Solution



First, by the absolute convergence test, [tex]\sum \frac{(-1)^{n}}{n+n^{2}}[/tex] should converge if [tex]\sum \left|\frac{(-1)^{n}}{n+n^{2}}\right|[/tex] converges.



Second, [tex]\sum \left|\frac{(-1)^{n}}{n+n^{2}}\right| = \frac{1}{n+n^{2}}< \sum 1/n^{2}[/tex]

Because the sum 1/n^2 converges, by the comparison test, [tex]\sum \left|\frac{(-1)^{n}}{n+n^{2}}\right|[/tex] converges.

Which means that [tex]\sum \frac{(-1)^{n}}{n+n^{2}}[/tex] converges as well (by the absolute convergence test).
 
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Your proof appears to be valid.
 

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