Proving Cosine Identity: Is cos(t+2π) the Same as cos(t)?

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SUMMARY

The discussion centers on the cosine identity, specifically whether \(\cos(t) = \cos(t + 2\pi)\). User Casey initially attempts to apply the cosine sum formula, \(\cos(\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta\), but mistakenly substitutes values leading to confusion. The resolution highlights that \(\cos(2\pi) = 1\), confirming that \(\cos(t + 2\pi) = \cos(t)\) is indeed valid. The importance of proper syntax in LaTeX formatting is also emphasized.

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Saladsamurai
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\cos (t)=\cos(t+2\pi)

I know it is kind of silly, but I need to do it.

I could have sworn that a sum formula would have worked, ie.,
\cos(\alpha+\beta)=\cos \alpha \cos \beta -\sin \alpha \sin \beta

but when I sub in t and2\pi for the RHS, I am getting -\cos t

Where did I go wrong...

Casey

Edit: IDK why LaTex alpha isn't showing on RHS
 
Last edited:
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Saladsamurai said:
\cos (t)=\cos(t+2\pi)

I know it is kind of silly, but I need to do it.

I could have sworn that a sum formula would have worked, ie.,
\cos(\alpha+\beta)=\cos\alpha\cos\beta-\sin\alpha\sin\beta

but when I sub in t and2\pi for the RHS, I am getting -\cos t

Where did I go wrong...

Casey

What is cos (2 pi)? (You're going to kick yerself...)

P.S. One of the alphas wasn't displaying because you wrote "alpa"; the cos t didn't display because you left out a space between "cos" and "t"; TeX is unforgiving that way...
 
dynamicsolo said:
What is cos (2 pi)? (You're going to kick yerself...)

P.S. One of the alphas wasn't displaying because you wrote "alpa"; the cos t didn't display because you left out a space between "cos" and "t"; TeX is unforgiving that way...

Ouch! I did not know it was possible to kick myself there:cry: ...
+1

Thanks,
Casey
 

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