Proving Discrete Topology: Topology Problem on Set of Integers

  • Thread starter Thread starter mathshelp
  • Start date Start date
  • Tags Tags
    Topology
Click For Summary
SUMMARY

The discussion focuses on proving that a topology U on the set of integers Z, where every infinite subset is open, is indeed the discrete topology. The proof involves demonstrating that for any element in Z, there exist two infinite subsets that intersect at that element. By showing that every singleton subset is open and utilizing arbitrary unions, it is established that U encompasses all subsets of Z, confirming that U is the power set of Z.

PREREQUISITES
  • Understanding of topology concepts, specifically discrete topology.
  • Familiarity with set theory and the properties of infinite subsets.
  • Knowledge of basic proof techniques in mathematics.
  • Ability to work with unions and intersections of sets.
NEXT STEPS
  • Study the properties and definitions of discrete topology in detail.
  • Explore examples of infinite subsets and their implications in topology.
  • Learn about the power set and its significance in set theory.
  • Investigate other types of topologies and their characteristics.
USEFUL FOR

This discussion is beneficial for mathematics students, particularly those studying topology, as well as educators and anyone interested in the foundational aspects of set theory and topology proofs.

mathshelp
Messages
11
Reaction score
0

Homework Statement



Let U be a topology on the set Z of integers in which every infinite subset
is open. Prove that U is the discrete topology, in which every subset is open.

Homework Equations



Just the definition of discrete topology

The Attempt at a Solution



I'm not sure where to start!
 
Physics news on Phys.org
yeah i think that this is the same method used in the other thread someone else made with the second part of this question. find two infinite subsets of Z that intersect at a single point. then by doing this for every element of Z you can show that every 1 element subset of Z is open. then u can take arbitrary unions to show every possible subset of Z is open and hence U is the power set of Z.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
3
Views
2K
Replies
20
Views
5K
Replies
23
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K