Proving EM Waves Equations: E = Emsin(kx-ωt) and B = Bmsin(kx-ωt)

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Homework Help Overview

The discussion revolves around proving that the electric field E = Emsin(kx-ωt) and the magnetic field B = Bmsin(kx-ωt) satisfy specific differential equations related to electromagnetic waves. The problem is situated within the context of electromagnetic theory.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants suggest substituting the expressions for E and B into the differential equations and taking derivatives to explore the relationships. There is also mention of needing to relate μ₀, ε₀ to k and ω.

Discussion Status

Some participants have provided guidance on how to approach the problem by suggesting substitution and derivative operations. There is recognition of potential complications with the resulting equations, particularly concerning the presence of B_m and E_m on different sides of the equations.

Contextual Notes

There is an indication that the original poster is struggling with the setup of the problem and has requested guidance multiple times. The discussion reflects a need for clarification on the mathematical relationships involved in the equations.

noppawit
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Show that the electric field: E = Emsin(kx-ωt) and magnetic field: B=Bmsin(kx-ωt) satisfy the following equations:

[tex]-\frac{\partial B}{\partial x} = \mu_{0}\epsilon_{0}\frac{\partial E}{\partial t}[/tex]

and

[tex]\frac{\partial E}{\partial x} = -\frac{\partial B}{\partial t}[/tex]


I have no idea about this. Would you please guide me for solving this.

Thanks.
 
Last edited:
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Your equations didn't come out properly so we can't help you.
 
Sorry for my bad Latex typing. :redface:

I've edited.
 
noppawit said:
Show that the electric field: E = Emsin(kx-ωt) and magnetic field: B=Bmsin(kx-ωt) satisfy the following equations:

[tex]-\frac{\partial B}{\partial x} = \mu_{0}\epsilon_{0}\frac{\partial E}{\partial t}[/tex]

and

[tex]\frac{\partial E}{\partial x} = -\frac{\partial B}{\partial t}[/tex]


I have no idea about this. Would you please guide me for solving this.

Thanks.

In a situation like this, the usual procedure is to substitute the two given expressions into the differential equation, take the derivatives and see what happens. As I look at what you've been given (without working it out myself) I think you may have to figure out how to relate [tex]\mu_o \epsilon_o[/tex] to k and [tex]\omega[/tex].
That should get you started. Let us know if you run into trouble.
 
AEM said:
In a situation like this, the usual procedure is to substitute the two given expressions into the differential equation, take the derivatives and see what happens. As I look at what you've been given (without working it out myself) I think you may have to figure out how to relate [tex]\mu_o \epsilon_o[/tex] to k and [tex]\omega[/tex].
That should get you started. Let us know if you run into trouble.

Upon reading my previous post, I see a small problem with what I wrote. When you substitute the expressions for E an B into each equation, you'll end up with a [tex]B_m[/tex] on one side and a [tex]E_m[/tex] on the other. That's a nuisance. However, I'll bet you can figure out a way to combine those two equations into one equation and then do the substitution.
 
noppawit said:
Show that the electric field: E = Emsin(kx-ωt) and magnetic field: B=Bmsin(kx-ωt) satisfy the following equations:

[tex]-\frac{\partial B}{\partial x} = \mu_{0}\epsilon_{0}\frac{\partial E}{\partial t}[/tex]

and

[tex]\frac{\partial E}{\partial x} = -\frac{\partial B}{\partial t}[/tex]


I have no idea about this. Would you please guide me for solving this.

Thanks.

IIRC, you would start with Maxwell's equations...
 

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