Proving Existence of Positive Integer Multiple with 0s & 1s

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Homework Help Overview

The problem involves proving the existence of a positive integer multiple of a given positive integer k, such that the multiple consists solely of the digits 0 and 1. The original poster seeks guidance on how to approach this proof using the pigeonhole principle.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the sequence of numbers formed by repeating the digit 1, questioning how many possible remainders exist when these numbers are divided by k. Some express uncertainty about how to utilize this sequence effectively.

Discussion Status

The discussion is ongoing, with participants sharing insights and approaches. Some have suggested a method involving the pigeonhole principle, while others are exploring different cases based on modular arithmetic. There is a mix of ideas, and no consensus has been reached yet.

Contextual Notes

Participants are navigating the constraints of the problem, including the requirement to use the pigeonhole principle and the nature of the digits in the integer multiple. There is mention of potential complications based on the properties of the number 10 in modular arithmetic.

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Homework Statement


Let k be any positive integer. Prove that there exists a positive
integer multiple n of k such that the only digits in n are 0s and
1s. (Use the pigeonhole principle.)


Homework Equations


The General Pigeonhole Principle
If more than mk things are distributed into k boxes then
at least one box receives more than m things.


The Attempt at a Solution


Don't know where to start off. I just need a bit of a nudge and hopefully that'll get me started. thanks :)
 
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Think about the sequence of numbers {1,11,111,1111,11111,...}. How many possible remainders are there when you divide by k?
 
Dick said:
Think about the sequence of numbers {1,11,111,1111,11111,...}. How many possible remainders are there when you divide by k?

Very nice! I thought about this problem on the drive home and came up with a solution, but it's a bit more complicated, entailing two cases depending on whether 10 is a unit or a zero divisor mod k. Your solution is much quicker and more elementary. On the other hand, I think my method might find the smallest possible answer, but I haven't written down the details yet.
 
jbunniii said:
Very nice! I thought about this problem on the drive home and came up with a solution, but it's a bit more complicated, entailing two cases depending on whether 10 is a unit or a zero divisor mod k. Your solution is much quicker and more elementary. On the other hand, I think my method might find the smallest possible answer, but I haven't written down the details yet.

Yeah, it is nice. This is sort of a classic problem, I've seen it at least once before. It's classic pigeonhole. I didn't make up the solution. I just remembered it. I hadn't even thought about finding the smallest solution. If you can do that it would be interesting.
 
Last edited:
Dick said:
Think about the sequence of numbers {1,11,111,1111,11111,...}. How many possible remainders are there when you divide by k?

This is an interesting question but can't figure out what to do! What do you do with the sequence {1,11,111,...}?
 
aldebaran19 said:
This is an interesting question but can't figure out what to do! What do you do with the sequence {1,11,111,...}?

You don't do anything in particular with it as a sequence. You just think about the possible values of the remainders after dividing by k of those values. Then think 'pigeonhole principle'.
 
thanks for all the help, guys, especially Dick. i was able to get it from the first post you gave :)
 

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