Proving Function Equations: f(x) and g(x) with O(1/(x^2))

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Homework Help Overview

The discussion revolves around proving an equation involving two functions, f(x) and g(x), as x approaches infinity. The functions are defined with integrals and trigonometric expressions, and the context is rooted in mathematical analysis.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to prove a relationship between f(x) and g(x) as x approaches infinity, expressing uncertainty about their methods. Some participants question the validity of the problem due to a perceived typo in the source material.

Discussion Status

Some participants have offered insights into the problem, including potential methods involving integration by parts and derivative estimations. However, there is no explicit consensus on the approach, and the original poster remains uncertain about how to proceed.

Contextual Notes

There is mention of a typo in the original problem statement from the Chinese edition of the textbook, which has led to confusion regarding the proof. The original poster indicates they are a high school student, which may influence their approach to the problem.

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Homework Statement


Let's definite the function f(x)=∫(from x to x+1)sin(t^2)dt



Homework Equations


There is another function of x:
g(x)=cos(x^2)/2x-cos((x+1)^2)/2(x+1)


The Attempt at a Solution


Prove that when x→+∞,there is the equation:
f(x)=g(x)+O(1/(x^2))
Here the O(u) means that when u→0, the O(u) is at least infinite small comparable to the infinite small quantity u.

I am only a 12 grade high school student, so I have no methods to solve this. I will be grateful if you could give me some advice. This is a problem from the exercises of the Mathematical Analysis by V.A.Zorich, chapter 6, Volume I.
 
Last edited:
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Ha, I have solved this question. I got this problem from the Chinese Edition of the Zorich Analysis and it has a typo so I could not prove this. The problem in the English Edition is correct.

Consider ((cos(t^2))/t)'=-2sin(t^2)-cos(t^2)/(t^2)
The second part of the right side could be estimated smaller than 1/(x^2). So the problem solved.
 
Write:

[tex] \cos x^{2}=\frac{2x\cos x^{2}}{2x}[/tex]

and use integration by parts.
 
hunt_mat said:
Write:

[tex] \cos x^{2}=\frac{2x\cos x^{2}}{2x}[/tex]

and use integration by parts.

Yes, I have already known that.
I could not solve it because there is a typo in my Chinese Edition of the book.
 

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