Proving Heine-Borel Theorem: A Compactness Characterization in Metric Spaces

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SUMMARY

The forum discussion centers on the Heine-Borel theorem, specifically its characterization in metric spaces. It establishes that a subset of R^n is compact if and only if it is closed and bounded. The discussion highlights two proof methods: one using topological definitions and the other utilizing the Bolzano-Weierstrass theorem. Additionally, it emphasizes a more insightful approach that leverages the completeness of R^n to demonstrate that boundedness implies total boundedness, reinforcing the theorem's applicability beyond R^n.

PREREQUISITES
  • Understanding of the Bolzano-Weierstrass theorem
  • Familiarity with metric spaces and their properties
  • Knowledge of topological definitions of compactness
  • Concept of total boundedness in metric spaces
NEXT STEPS
  • Study the proof of the Bolzano-Weierstrass theorem in detail
  • Explore the concept of total boundedness in various metric spaces
  • Learn about the implications of the Heine-Borel theorem in functional analysis
  • Investigate the differences between bounded and totally bounded sets in metric spaces
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Mathematicians, students of real analysis, and anyone interested in the properties of compactness in metric spaces will benefit from this discussion.

quasar987
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In my book, they first prove Bolzano-Weierstrass (compact iff sequentially compact), then they prove a characterization of compactness for metric spaces: "A metric space M is compact iff it is complete and totally bounded." As a corollary of this, we get yet another characterization of compactness: "A subset A of a complete metric M space is compact iff it is closed in M and totally bounded."

Then they embark on the adventure of proving Heine-Borel (a subset of R^n is compact iff it is closed and bounded). They go about this in two ways. The first way sets out to prove the result using only the topological definition of compactness. After 3 lemmas the job is done. The second way uses the characterization by sequences (B-W) and after a dozen lines of reasoning, the job is done.

But it seems to me that they have left out the easiest and perhaps more enlightening way. Indeed, we already know that the metric space R^n is complete. Therefor, by the corollary I talked about, it suffices to show that in R^n, bounded ==> totally bounded. This way is more enlightening IMO because it actually shows that H-B is not a result that is restricted to R^n as the statement of the thm leads to believe. Rather, it suffices that a metric space M be complete that the the metric be not so exotic as to make a distinction btw bounded and totally bounded!

Or am I mistaken somewhere?
 
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You're not mistaken. In fact, the corollary you've given is sometimes called the "metric space Heine-Borel theorem."
 

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