Proving Intermediate Value Property: Function Analysis

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Homework Help Overview

The discussion revolves around demonstrating that a specific function satisfies the Intermediate Value Property (IVP). Participants are exploring the definition and implications of the property in the context of function analysis.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses uncertainty regarding the definition of the Intermediate Value Property and its implications for their problem. Some participants attempt to clarify the property by stating that it requires the image of every interval in the domain to also be an interval. Others propose a specific example involving selected values within an interval to illustrate the concept, questioning whether this is sufficient for a proof.

Discussion Status

The discussion is ongoing, with participants providing clarifications and examples. There is no explicit consensus on the sufficiency of the proposed example for proving the property, indicating that further exploration of the concept is needed.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of their explorations and the completeness of their examples.

KF33
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Homework Statement


I need to show the attached function satisfies the Intermediate Value Property.

Homework Equations

The Attempt at a Solution


I looked at the property definition, but I am really unsure what is being stated. I think if I knew what the property was stating, I could do the problem.
 

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a function has the IV property if the image of every interval is an interval. i.e. if for every interval [x1,x2] in the domain, the set of values f(x), for all x with x1 ≤ x ≤ x2, is also an interval.
 
Is it enough to say an interval could be [-10,0]. Then I select x1 to be -9 and x2 to be -1. f(x1)=-.412 and f(x2)=-.841. I look and select k to be between those and find a c value which f(c)=k.
 
KF33 said:
Is it enough to say an interval could be [-10,0]. Then I select x1 to be -9 and x2 to be -1. f(x1)=-.412 and f(x2)=-.841. I look and select k to be between those and find a c value which f(c)=k.
That's a single example, well, not even a complete example. Definitely not a proof.
 

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