Proving Inverse Function Continuity at Limit Point Q

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SUMMARY

The discussion focuses on proving the continuity of the inverse function at a limit point Q, specifically showing that if f(P) approaches 3 as P approaches Q, then 1/f(P) approaches 1/3. The key approach involves using the epsilon-delta definition of limits, where the transformation |1/f(P) - 1/3| = |f(P) - 3| / |f(P)| is crucial. Participants emphasize the importance of ensuring that f(P) does not approach zero to maintain the validity of the limit transformation.

PREREQUISITES
  • Understanding of epsilon-delta definitions of limits
  • Familiarity with continuity concepts in real analysis
  • Basic knowledge of functions and their inverses
  • Experience with limit points in ℝ^n
NEXT STEPS
  • Study the epsilon-delta definition of continuity in detail
  • Explore the properties of limits involving inverse functions
  • Learn about the implications of limit points in real analysis
  • Review examples of proving continuity for various functions
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Students of real analysis, mathematicians focusing on continuity and limits, and educators teaching advanced calculus concepts.

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Homework Statement



Suppose f is a function defined on a set ##S## in ##ℝ^n## and suppose ##Q## is a limit point of ##S##.

If ##f(P) → 3## as ##P → Q## prove from first principles that ##\frac{1}{f(P)} → \frac{1}{3}## as ##P → Q##.

Homework Equations





The Attempt at a Solution



I'm a bit rusty with these.

I know : ##\forall ε'>0, \exists δ'>0 \space | \space 0 < |P-Q| < δ' \Rightarrow |f(P) - 3| < ε'##

I want : ##\forall ε>0, \exists δ>0 \space | \space 0 < |P-Q| < δ \Rightarrow |1/f(P) - 1/3| < ε##

For some reason I'm blanking on what to do next.
 
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HI Zondrina! :smile:

Hint: |1/f(P) - 1/3| = |f(P) - 3| / |f(P)| :wink:
 
tiny-tim said:
HI Zondrina! :smile:

Hint: |1/f(P) - 1/3| = |f(P) - 3| / |f(P)| :wink:

Thanks tim, cleaned up nicely :)
 

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