Proving Limits: δ = min(δ1,δ2) Meaning Explained

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Homework Help Overview

The discussion revolves around understanding the notation "δ = min(δ1,δ2)" in the context of proving limits in calculus. Participants are exploring the meaning of this expression and its implications for the values of δ1 and δ2.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of the minimum function in this context, questioning how δ relates to δ1 and δ2. There is also a discussion about whether the source material provides adequate definitions for the notation used.

Discussion Status

Some participants are providing interpretations of the notation, while others are confirming or questioning these interpretations. There is an ongoing exploration of the definitions and implications of the terms involved.

Contextual Notes

There is mention of potential confusion due to the lack of a glossary in the source material, which may affect participants' understanding of the notation.

Miike012
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The chapter I am reading is on proving limits... The terms "δ = min(δ1,δ2)" has came up a few times but what does it mean?

My guess is that the distances δ1 and δ2 are some where in the interval of the distance δ about some x value.
 
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Miike012 said:
The chapter I am reading is on proving limits... The terms "δ = min(δ1,δ2)" has came up a few times but what does it mean?

My guess is that the distances δ1 and δ2 are some where in the interval of the distance δ about some x value.

Typically, min(δ1,δ2) means the smaller of δ1 and δ2, or at least it does in most books and papers. Does your source really not have a glossary of notation?

RGV
 
Ok it says the min of two numbers x and y is denoted min(x,y).. so I am guessing what I posted above that "min(δ1,δ2)" means δ1= δ if δ1<δ2 and vise versa. is that right?
 
Miike012 said:
Ok it says the min of two numbers x and y is denoted min(x,y).. so I am guessing what I posted above that "min(δ1,δ2)" means δ1= δ if δ1<δ2 and vise versa. is that right?
It's the other way around.

δ = δ1 if δ1 is the smaller of the two numbers, and

δ = δ2 if δ2 is the smaller of the two numbers.

If δ1 = δ2, then set δ to either number.
 

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