Proving Modulus of Rational Expression is Equal to 1

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SUMMARY

The modulus of the rational expression |\frac{e^{2i\theta} -2e^{i\theta} - 1}{e^{2i\theta} + 2e^{i\theta} -1}| is proven to equal 1 using Euler's formula, where e^{i\theta} is expressed as cos(θ) + i sin(θ). The solution involves simplifying the expression by substituting e^{i\theta} and applying properties of complex numbers. This problem is a step in a larger mathematical context, as discussed in the referenced Math Stack Exchange thread.

PREREQUISITES
  • Understanding of Euler's formula: e^{i\theta} = cos(θ) + i sin(θ)
  • Complex number manipulation and properties
  • Knowledge of modulus of complex expressions
  • Familiarity with rational expressions in mathematics
NEXT STEPS
  • Study the derivation of Euler's formula and its applications in complex analysis
  • Learn about the properties of complex modulus and their implications
  • Explore rational expressions and their simplification techniques
  • Review related problems on Math Stack Exchange for deeper insights
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Students studying complex analysis, mathematicians tackling rational expressions, and anyone interested in the properties of complex numbers and their applications in proofs.

Poopsilon
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Homework Statement



Prove [tex]|\frac{e^{2i\theta} -2e^{i\theta} - 1}{e^{2i\theta} + 2e^{i\theta} -1}| = 1[/tex]

Homework Equations


The Attempt at a Solution



I feel like this should be fairly simple, anyone have any hints? Also this is just one step in an attempt to solve a much larger problem, so don't feel the need to be overly cryptic. Also that means I'm not entirely sure that it's true (but I think it is).
 
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Poopsilon said:

Homework Statement



Prove [tex]|\frac{e^{2i\theta} -2e^{i\theta} - 1}{e^{2i\theta} + 2e^{i\theta} -1}| = 1[/tex]



Homework Equations





The Attempt at a Solution



I feel like this should be fairly simple, anyone have any hints? Also this is just one step in an attempt to solve a much larger problem, so don't feel the need to be overly cryptic. Also that means I'm not entirely sure that it's true (but I think it is).

I would use the facts that ei 2θ = cos(2θ) + i sin(2θ) and ei θ = cos(θ) + i sin(θ) and see where that took me.
 

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