Proving Nonzero Vector Intersection in 3D Subspaces of R5

Click For Summary
SUMMARY

In the discussion, participants address the problem of proving that two three-dimensional subspaces, V and W, of R5 must share a nonzero vector. The subspaces are represented with specific vectors, V = { (1, 0, 0, 0, 0), (0, 1, 0, 0, 0), (0, 0, 1, 0, 0) } and W = { (0, 0, 0, 1, 0), (0, 0, 0, 0, 1), (1, 1, 0, 0, 0) }. The discussion emphasizes the importance of understanding linear independence and the dimensionality of vector spaces, leading to the conclusion that the intersection of V and W must contain at least one nonzero vector due to the properties of linear combinations in R5.

PREREQUISITES
  • Understanding of vector spaces in linear algebra
  • Knowledge of linear independence and basis vectors
  • Familiarity with the concepts of dimensionality in R5
  • Ability to perform vector operations and linear combinations
NEXT STEPS
  • Study the properties of linear independence in vector spaces
  • Learn about the intersection of subspaces in linear algebra
  • Explore the concept of basis vectors in R5
  • Investigate the implications of the dimension theorem for vector spaces
USEFUL FOR

Students and educators in linear algebra, mathematicians interested in vector space theory, and anyone seeking to understand the intersection properties of subspaces in higher-dimensional spaces.

RyanV
Messages
12
Reaction score
0

Homework Statement


Prove that if V and W are three dimensional subspaces of R5, then V and W must have a nonzero vector in common.


Homework Equations


NA


The Attempt at a Solution


I've attempted to set up the problem by writing out,

V = { (1, 0, 0, 0, 0), (0, 1, 0, 0, 0), (0, 0, 1, 0, 0) }
W = { (0, 0, 0, 1, 0), (0, 0, 0, 0, 1), (1, 1, 0, 0, 0) }

After that, I'm lost.

I don't really like vector spaces because I don't understand it very well. So could whoever explain please explain thoroughly? =P I would help a lot because I want to know what's going on! hehe, thanks in advance =)
 
Physics news on Phys.org
rather than narrowing in on a single case, think aobut linear independence... what is the maximal number of linearly independent vectors, in any subspace of R^3?

similarly, how many vectors are in a the basis for R^5?
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 7 ·
Replies
7
Views
2K