Proving Nullspaces: Null(M) = Null((M^T)(M)) | Matrix Homework

  • Thread starter Thread starter Big-oh
  • Start date Start date
  • Tags Tags
    Matrix
Click For Summary
SUMMARY

The discussion centers on proving the equality of nullspaces for an mxn matrix M, specifically that Null((M^T)(M)) = Null(M). The user successfully demonstrated that Null(M) is a subset of Null((M^T)(M)), establishing the first part of the proof. The challenge lies in proving the reverse inclusion, where the user explores the implications of a vector x being in Null((M^T)(M)). The discussion emphasizes the importance of understanding the properties of matrix transposition and nullspaces in linear algebra.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically nullspaces.
  • Familiarity with matrix transposition and its properties.
  • Knowledge of the relationship between linear transformations and their nullspaces.
  • Experience with proofs in mathematics, particularly set theory.
NEXT STEPS
  • Study the properties of nullspaces in linear transformations.
  • Learn about the implications of the rank-nullity theorem in linear algebra.
  • Explore examples of proving set equality in mathematical proofs.
  • Investigate the geometric interpretation of nullspaces and their significance in vector spaces.
USEFUL FOR

Students and educators in linear algebra, mathematicians focusing on matrix theory, and anyone interested in understanding the properties of nullspaces and their applications in solving linear equations.

Big-oh
Messages
5
Reaction score
0

Homework Statement



Given an mxn matrix M, prove that Null((M^T)(M)) = Null(M)

Where M^T is the transpose of the matrix M.

The Attempt at a Solution



I was able to get the first part (Null(M) is a subset of Null((M^T)(M))), but I'm just having trouble proving the other way around. I pick any vector in Null((M^T)(M)), but unsure of what to do after that.
 
Physics news on Phys.org
The standard way to prove that to sets, A and B, say, are equal is to prove A is a subset of B then prove that B is a subset of A. And you prove A is a subset of B by starting "if x is in A" and then use the properties of A and B to conclude "x is in B".

Here, the two sets are Null(M) and Null(M^T(M)). If x is in Null(M) then M(x)= 0. It then follows immediately that M^T(Mx)= M^T(0)= 0. That's the easy way. If x is in Null(M^T(M)) then M^T(M(x))= 0. Obviously, if M(x)= 0 we are done. What can you say about non-zero x such that M^t(x)= 0?
 

Similar threads

Replies
8
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
14
Views
7K
Replies
3
Views
2K