Proving Orthogonality of Legendre Polynomials

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 3K views
Logarythmic
Messages
277
Reaction score
0
Problem:

Show that

[tex]\int_{-1}^{1} x P_n(x) P_m(x) dx = \frac{2(n+1)}{(2n+1)(2n+3)}\delta_{m,n+1} + \frac{2n}{(2n+1)(2n-1)}\delta_{m,n-1}[/tex]

I guess I should use orthogonality with the Legendre polynomials, but if I integrate by parts to get rid of the x my integral equals zero.
Any tip on how to start working with this?
 
Physics news on Phys.org
First thought would be to use one of the recursion relationships on xPn(x).

For example -

[tex](l+1)P_{l+1}(x)\,-\,(2l+1)xP_l(x)\,+\,lP_{l-1}(x)\,=\,0[/tex]

BTW, has one shown -

[tex]\int_{-1}^{1} P_n(x) P_m(x) dx = \frac{2}{2n+1}\delta_{m,n}[/tex]

That was demonstrated here on PF recently.
 
Last edited:
Yes, I've got the last equation and I'll try with the recursion, thank you. =)
 
Another thing I would recommend is to try using the Rodriguez formula for the Legendre polynomials, then play games with integration by parts.
 
And why is that? I solved the problem by the way. Pretty simple when you know about the recursion relationships.