Proving Periodicity for a Function with Two Elements and a Constant Period

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Homework Help Overview

The discussion revolves around proving the periodicity of a function defined in two segments, f(t), where one segment is 1 + kt for 0 < t < 1 and the other is 1 for 1 < t < 2. The original poster seeks to establish that the period of f is 2 when k is not equal to zero, while also grappling with how to graph the function and prove this mathematically.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the definition of the "elements of f(t)" and seek clarification on the function's structure. There is discussion about the implications of k being non-zero on the graph's slope and the periodicity condition f(t + 2) = f(t). Some participants express concern about the function's definition at specific points and the validity of the given information.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the function's definition and its implications for periodicity. Some guidance has been offered regarding the nature of the function's slope based on the value of k, but no consensus has been reached on the proof or the graphical representation.

Contextual Notes

There are concerns regarding the function's definition at critical points (0, 1, and 2) and the clarity of the problem statement as presented by the original poster. The discussion reflects uncertainty about whether the periodicity condition is given or needs to be proven.

darkmagic
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Homework Statement



The elements of f(t) are 1+kt and t here are 0<t<1
the other element is 1 and t here are 1<t<2.

f(t+2)=f(t)

prove if k is not equal to zero, the period f is 2.

i know the graph of element 1 but how should I graph the other element with k.
Based from the graph, the period is 2.

How should I prove that using mathematical statement?

Homework Equations



The problem is all about fundamental period
 
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What do you mean "elements of f(t)"?
I don't have any idea of what you saying here:
darkmagic said:
The elements of f(t) are 1+kt and t here are 0<t<1
the other element is 1 and t here are 1<t<2.

Are you saying that f(t) = 1 + kt, if 0 < t < 1, and f(t) = 1, if 1 < t < 2?
Is f(t + 2) = f(t) given, or is that what you're trying to prove?
 
thats what i am saying. f(t+2) =f(t) is given. what I am trying to prove is that if k is not equal to zero, the period f is 2.
how i should i plot the 1+kt?
 
Last edited:
Well, you don't know k, other than it isn't zero, so you have a line segment with pos. slope if k > 0, and neg. slope if k < 0. It doesn't really matter whether it slopes up or down, just so long as the line isn't horizontal.
 
ok so how I prove by mathematical statement that the period f is 2? can this be
or it can only be proved by graph?
 
A function is periodic with period p iff f(x + p) = f(x) for all x. (See the definition on this Wikipedia page: http://en.wikipedia.org/wiki/Periodic_function.)

So the information that you tell me is given would seem to do the trick except when k = 0. In that case, f(x) = 1 at most points, which would imply that the period was smaller than 2. I say "at most points" because from the information in your post, f(x) is not defined at x = 0, x = 1, and x = 2.

Are you sure you have posted the problem exactly the way it reads? It bothers me that f isn't defined at 0, 1, and 2, and it also bothers me that you are given that f(t + 2) = f(t), since that's essentially what you need to prove.
 

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