Proving Projection Matrices Using Definition | Exam Practice Problems

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SUMMARY

This discussion centers on proving properties of projection matrices in linear algebra, specifically that if projV(u) = A, then A = A2 and A = AT. The definition of projection onto a subspace V in Rm is provided, emphasizing that the projection of a vector b onto V results in a unique vector p in V, where b - p is in the orthogonal complement of V. The proof involves showing that re-projecting a vector leads to the same result, confirming A = A2, and utilizing the dot product properties to establish A = AT.

PREREQUISITES
  • Understanding of linear algebra concepts, particularly projection matrices.
  • Familiarity with the definitions of subspaces and orthogonal complements in Rm.
  • Knowledge of vector dot products and their properties.
  • Experience with matrix operations, including transposition and multiplication.
NEXT STEPS
  • Study the properties of projection matrices in linear algebra.
  • Learn about the relationship between linear transformations and their matrix representations.
  • Explore the concept of orthogonal complements in vector spaces.
  • Investigate the implications of the Spectral Theorem for symmetric matrices.
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Students preparing for exams in linear algebra, educators teaching matrix theory, and anyone seeking to deepen their understanding of projection matrices and their properties.

renolovexoxo
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I'm doing practice problems for my exam, but I don't really know how to get this one. I'd like to just be able to understand it before my test if anyone can help explain it!

Prove from the definition of projection (given below) that if projv=u(sub A) then A=A^2 and A=A^T. (Hint: for the latter, show that Ax dot y=x dot Ay for all x,y. It may be helpful to write x and y as the sum of vectors in V and V perp.

Def: Let V in Rm be a subspace, and let b be an element of Rm. We define the projection of b onto V to be the unique vector p that is an element of V with the property that b-p is an element of V-perp. We write p=projv b
 
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renolovexoxo said:
I'm doing practice problems for my exam, but I don't really know how to get this one. I'd like to just be able to understand it before my test if anyone can help explain it!

Prove from the definition of projection (given below) that if projv=u(sub A) then A=A^2 and A=A^T. (Hint: for the latter, show that Ax dot y=x dot Ay for all x,y. It may be helpful to write x and y as the sum of vectors in V and V perp.

Def: Let V in Rm be a subspace, and let b be an element of Rm. We define the projection of b onto V to be the unique vector p that is an element of V with the property that b-p is an element of V-perp. We write p=projv b

Hey renolovexoxo and welcome to the forums.

For the A^2 = A proof, we are given that the projection must be a unique vector which means that if re-project an existing vector that is projected onto some projection subspace that it will be the same. What does this imply about reprojecting an existing projection and how that relates to A^2 (Hint: if Proj(X) = AX, and Proj(AX) = Proj(X) then what is the implications?) You will have to probably use the definitions you have been given for an actual projection to get a proper proof expected by your professor/teacher, but the above idea should give you a better hint.

For the A^T I think the hint is a very good one. I would recommend you expand out the definitions of Ax dot y and x dot Ay where A and Aperp form your initial space: In other words, dim(A) + dim(A_perp) = dim(Rm) = m.
 

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