Proving properties of lim sup. Good attempt at proof

  • Thread starter Thread starter tamintl
  • Start date Start date
  • Tags Tags
    Proof Properties
Click For Summary
SUMMARY

The statement 'if (cn) and (dn) are bounded sequences of positive real numbers then: lim sup (cndn) = (lim sup cn)(lim sup dn)' is true. The proof relies on the theorem that states lim(cndn) equals lim cn times lim dn, which holds under the conditions of bounded sequences. However, it is crucial to note that while bounded sequences may have convergent subsequences, they do not necessarily converge themselves. This distinction is vital for understanding the properties of bounded sequences in real analysis.

PREREQUISITES
  • Understanding of bounded sequences in real analysis
  • Familiarity with the concept of limit superior (lim sup)
  • Knowledge of convergence criteria for sequences
  • Basic principles of real analysis theorems
NEXT STEPS
  • Study the properties of bounded monotone sequences and their convergence
  • Explore examples of bounded sequences that do not converge
  • Learn about the implications of the Bolzano-Weierstrass theorem
  • Investigate the relationship between subsequences and convergence in real analysis
USEFUL FOR

Students and educators in mathematics, particularly those focusing on real analysis, as well as anyone seeking to deepen their understanding of sequence convergence and properties of bounded sequences.

tamintl
Messages
74
Reaction score
0
[/itex]

Homework Statement


Is the following statement true or false: 'if (cn) and (dn) are bounded sequences of positive real numbers then:

lim sup (cndn) = (lim sup cn)(lim sup dn)

Homework Equations


The Attempt at a Solution


for all n in the positive reals. cn and dn are bounded.

Since cn and dn are bounded we know they converge.

Hence, by the theorem lim(cndn)=lim cnlim dn we can say that lim(cn)=lim sup (cn) and lim(dn)=lim sup (dn)

Hence, lim sup (cndn) = (lim sup cn)(lim sup dn)

HENCE, TRUE!

******I am not sure about line 2 where I say bounded => converge. I know that you can say that converge means bounded but I don't know if I can do the reverse.*******
 
Physics news on Phys.org
tamintl said:
******I am not sure about line 2 where I say bounded => converge. I know that you can say that converge means bounded but I don't know if I can do the reverse.*******

You can't. You can say that a bounded monotone sequence converges and that a bounded sequence has a convergent subsequence. But a bounded sequence need not converge. You should be able to come up with a pretty simple example of a bounded sequence that does not converge (at least now that you know there is one). In the process of doing so, you may stumble across the answer to your problem.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K