Proving R[x] is a Principal Ideal Domain Implies R is a Field

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SUMMARY

To prove that if R[x] is a principal ideal domain, then R must be a field, one must establish that every non-zero element of R has a multiplicative inverse. The distinction between an integral domain and a field is critical; specifically, in a field, every non-zero element possesses an inverse, which is the crux of the proof. This conclusion is derived from the properties of ideals in R[x] and their implications on the structure of R.

PREREQUISITES
  • Understanding of integral domains and fields in abstract algebra
  • Familiarity with the properties of principal ideal domains
  • Knowledge of polynomial rings, specifically R[x]
  • Basic definitions and theorems related to multiplicative inverses
NEXT STEPS
  • Study the definitions and properties of integral domains and fields
  • Explore the structure and characteristics of principal ideal domains
  • Learn about polynomial rings and their ideal structures
  • Review proofs involving multiplicative inverses in abstract algebra
USEFUL FOR

Students of abstract algebra, mathematicians interested in ring theory, and anyone seeking to understand the relationship between polynomial rings and field properties.

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Homework Statement



Let R be an integral domain and suppose that R[x] is a principal ideal domain. Show that R is a field.


Homework Equations




I don't know where to start, I'm not familiar with this material. I was browsing through an abstract algebra book and found this. Would like an explanation of what it means, thank you.

The Attempt at a Solution

 
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The difference between an integral domain and a field is that every non-zero member of a field has a multiplicative inverse. That is what you need to prove.

(If you are not familiar with the material, why are you trying to do this problem? Wouldn't it be better to start at the beginning and read the book rather than "browsing"? Do you need definitions of "field" and "integral domain"?)
 

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