Proving Recursion relations for Bessel Functions

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The discussion revolves around solving recursion relations for Bessel functions, specifically J_{p+1}(x) and J_{p-1}(x), using given differential equations. Participants express confusion about whether to substitute values into J_{p} or to directly manipulate the equations to isolate J_{p-1}(x) and J_{p+1}(x). Clarification is provided that the correct approach involves applying calculus rules, such as the product rule, rather than relying on infinite series. The conversation highlights a common misunderstanding in transitioning from series manipulation to basic calculus techniques. Ultimately, the participant realizes the need to apply fundamental calculus rules to solve the problem effectively.
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Homework Statement


Solve equations 1) and 2) for J_{p+1}(x) and J_{p-1}(x). Add and subtract these two equations to get 3) and 4).


Homework Equations


1) \frac{d}{dx}[x^{p}J_{p}(x)] = x^{p}J_{p-1}(x)
2) \frac{d}{dx}[x^{-p}J_{p}(x)] = -x^{-p}J_{p+1}(x)
3) J_{p-1}(x) + J_{p+1}(x) = \frac{2p}{x}J_{p}(x)
4) J_{p-1}(x) - J_{p+1}(x) = 2J^{'}_{p}(x)


The Attempt at a Solution


My main problem is I'm not really sure what the question is asking me to do in the first part. Am I supposed to plug p+1 and p-1 into J_{p} on the left of each equation or am I supposed to simply solve equation 1) as J_{p-1}(x) = x^{-p}\frac{d}{dx}[x^{p}J_{p}(x)] and equation 2) as J_{p+1}(x) = -x^{p}\frac{d}{dx}[x^{-p}J_{p}(x)]? I tried this way and then differentiated the series and got two infinite series I didn't know what to do with.

Next, I tried to substitute J_{p+1} into J_{p} and I integrated on both sides and just got J_{p+1} = J_{p+1} after rearranging everything.

I feel like this isn't an overly difficult problem, but I just have no idea what direction to take with it.
 
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gametheory said:
My main problem is I'm not really sure what the question is asking me to do in the first part. Am I supposed to plug p+1 and p-1 into J_{p} on the left of each equation or am I supposed to simply solve equation 1) as J_{p-1}(x) = x^{-p}\frac{d}{dx}[x^{p}J_{p}(x)] and equation 2) as J_{p+1}(x) = -x^{p}\frac{d}{dx}[x^{-p}J_{p}(x)]? I tried this way and then differentiated the series and got two infinite series I didn't know what to do with.

Yes, it's saying the latter, but I don't know what you mean about getting infinite series; if you expand the derivative on the RHS in each case, you can just use the product rule to get one term with the Bessel function and one term with its derivative (and adding these or subtracting should give the two results).
 
Nevermind, you're right, I got it. All the other problems had us manipulate the bessel function as an infinite series and I was just used to doing this. Forgot to try basic rules from calculus...haha thanks
 

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