Proving Relatively Prime Property: Integers, gcd, and the Prime Divisor Problem

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SUMMARY

The discussion centers on proving that if a nonzero integer c is relatively prime to a set of integers a1, a2, ..., an, then c is also relatively prime to the product b = a1 * a2 * ... * an. The key definitions include the concept of relatively prime integers, defined by gcd(a, b) = 1. The solution approach involves using mathematical induction and Euclid's lemma, which states that if c divides the product ab and gcd(c, a) = 1, then c must divide b. This lemma is crucial for establishing the relationship between c and the product b.

PREREQUISITES
  • Understanding of gcd (greatest common divisor) and its properties
  • Familiarity with the concept of relatively prime integers
  • Knowledge of mathematical induction techniques
  • Comprehension of Euclid's lemma and its applications
NEXT STEPS
  • Study the proof of Euclid's lemma in detail
  • Practice problems involving gcd and relatively prime integers
  • Explore mathematical induction with various examples
  • Investigate applications of gcd in number theory
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Students studying number theory, mathematicians interested in properties of integers, and educators teaching concepts related to gcd and prime numbers.

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Homework Statement


I have to prove the following:
Let a1,a2, ...,an be integers and set b=a1*a2*...*an. If c is a nonzero integer and c is relatively prime to each ak, then c and b are relatively prime.

Homework Equations



Definition of relatively prime: Let a and b be integers, not both zero. if gcd(a,b)=1 then a and b are relatively prime.

The Attempt at a Solution



1. Let a1,a2, ...,an be integers and let b=a1*a2*...*an. Suppose there exists a nonzero integer c where c is relatively prime to each ak.

2. By defn, gcd(c,ak)=1

I need help showing that the gcd(c,a1*a2)=1

Thanks
 
Last edited:
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You don't need to suppose the existence of c; it is given by hyphotesis.

The best way to do this is to use induction on n and the following result (sometimes called Euclides' lemma): if c|ab and gcd(c,a)=1, then c|b.

If you haven't covered this lemma, argue like this: if gcd(c,a1*a2)>1, then there must be a common prime divisor p > 1 of c and a1*a2; p cannot divide a1 (because then gcd(a1,c)>1), so it must divide a2 and gcd(c,a2) > 1, and this is also impossible.
 
I was just looking at Euclids Lemma actually and wondering how I would prove that c|ab? Is it because c is relatively prime with each a therefore it must divide ab?

Thank you for your help once again
 
Last edited:

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