MHB Proving Series Convergence: Comparing $\sum y_n$ with $\sum \frac{y_n}{1+y_n}$

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The discussion focuses on proving the convergence of the series $\sum y_n$ given that $\sum \frac{y_n}{1+y_n}$ converges, with the assumption that $y_n \geq 0$. It is established that $y_n \geq \frac{y_n}{1+y_n}$, which suggests a relationship between the two series. The convergence of $\frac{y_n}{1+y_n}$ implies that $y_n \to 0$, allowing for the bounding of $1+y_n$ and subsequently $\frac{y_n}{1+y_n}$. A hint is provided that $\frac{2}{3}y_n$ can serve as a lower bound, indicating a potential path to apply the comparison test for convergence. The discussion emphasizes the importance of bounding techniques in establishing series convergence.
evinda
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Hello! (Wave)
We have a sequence $(y_n)$ with $y_n \geq 0$.
We assume that the series $\sum_{n=1}^{\infty} \frac{y_n}{1+y_n}$ converges. How can we show that the series $\sum_{n=1}^{\infty} y_n$ converges?

It holds that $y_n \geq \frac{y_n}{1+y_n}$.

If we would have to prove the converse we could use the comparison test. Could you give me a hint what we can do in this case?
 
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From $\dfrac{y_n}{1+y_n}\to0$ we can conclude that $y_n\to0$. Therefore, $1+y_n$ can be eventually bounded from above, say, by $3/2$. So, $\dfrac{y_n}{1+y_n}$ can be bounded from below by $\dfrac23y_n$.
 
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