Proving that Angular Moment is Conserved - Kepler's 2nd Law

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SUMMARY

Kepler's 2nd law of planetary motion states that the radius vector from the Sun to a planet sweeps out equal areas in equal time intervals, which can be mathematically expressed as \(\frac{dA}{dt} = \frac{L}{2m}\), where \(L\) represents angular momentum. The area swept by the planet is calculated using the formula \(A = \frac{1}{2} r^{2} \theta\), leading to the conclusion that angular momentum is conserved in the context of a planet orbiting the Sun. This conservation is directly linked to the principles outlined in Kepler's laws, affirming that angular momentum conservation is foundational to understanding planetary motion.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with angular momentum, defined as \(\vec L = \vec r \times m \vec v\)
  • Basic knowledge of calculus, particularly derivatives and area calculations
  • Concept of circular motion and forces acting on celestial bodies
NEXT STEPS
  • Study the derivation of Kepler's laws from Newtonian mechanics
  • Explore the implications of angular momentum conservation in multi-body systems
  • Learn about the mathematical representation of orbital mechanics
  • Investigate the role of gravitational forces in maintaining orbital paths
USEFUL FOR

Students of classical mechanics, astrophysics enthusiasts, and educators teaching planetary motion concepts will benefit from this discussion.

BOAS
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Homework Statement



Kepler’s 2nd law of planetary motion says that the radius vector drawn from the Sun to any planet sweeps out equal areas in equal time intervals. By considering the small area swept out by the radius vector in time dt, show that \frac{dA}{dt} = \frac{L}{2m} , where L is angular momentum. Then show that the angular momentum is conserved for this situation, thus proving Kepler’s 2nd law.

Homework Equations



\vec L = \vec r \times m \vec v

The Attempt at a Solution



This might be a little hard to follow without a diagram, but i'll do my best to label everything clearly.

The area of a sector is given by A = \frac{1}{2} r^{2} \theta, so the area swept out by the planet in time dt is given by \frac{dA}{dt} = \frac{1}{2} r^{2} \frac{d \theta}{dt}.

The velocity of the planet perpendicular to the radius vector is v_{p} = v \sin \phi where \phi is the angle between the radius and velocity vectors.

\frac{dA}{dt} = \frac{1}{2} r v \sin \phi

From the expression for the magnitude of the cross product rv \sin \phi = |\vec r \times \vec v|
Therefore, we can say \frac{dA}{dt} = \frac{L}{2m}. (after multiplying by a factor of 1/m).

I am confused by what it means to prove that angular momentum is conserved in this situation. I know how to prove that angular momentum is conserved for two bodies each exerting a force on one another, but I don't see the link to Kepler's second law.

Should I be understanding the 'situation' simply to mean a planet orbiting the sun, or can I use keplers second law to prove conservation of angular momentum?

This is a first year classical mechanics question, if that in any way affects how you'd respond.

thanks!
 
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BOAS said:
The area of a sector is given by A = \frac{1}{2} r^{2} \theta, so the area swept out by the planet in time dt is given by \frac{dA}{dt} = \frac{1}{2} r^{2} \frac{d \theta}{dt}.
What about changes in r?
I am confused by what it means to prove that angular momentum is conserved in this situation. I know how to prove that angular momentum is conserved for two bodies each exerting a force on one another, but I don't see the link to Kepler's second law.
Kepler's law follows from conservation of angular momentum and the equality you just derived.
Should I be understanding the 'situation' simply to mean a planet orbiting the sun, or can I use keplers second law to prove conservation of angular momentum?
That would be a circular argument.
 

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