Proving the Continuity From Below Theorem

Click For Summary
The discussion revolves around proving the continuity from below theorem in probability theory, specifically focusing on a monotone nondecreasing sequence of events. The user has defined a sequence of mutually exclusive events and is attempting to show that the union of these events equals the union of another sequence to apply the Countable Additivity formula. There is confusion regarding how to prove the second property of Countable Additivity by induction, with the user unsure about starting the proof. Suggestions are made to clarify the problem by providing a complete description and outlining the induction hypothesis. The thread highlights the need for clearer communication to effectively address the proof challenge.
Sai Alonzo

Homework Statement


Prove the continuity from below theorem.

Homework Equations

The Attempt at a Solution


So I've defined my {Bn} already and proven that it is a sequence of mutually exclusive events in script A. I need to prove that U Bi (i=1 to infinity) is equal to U Ai (i=1 to infinity) to use the Countable Additivity formula.

My prof states that I need to prove the 2nd property of Countable Additivity by Induction but I'm not really sure how to go about.
 
Physics news on Phys.org
Sai Alonzo said:

Homework Statement


Prove the continuity from below theorem. I don't see a theorem. Do you ?

Homework Equations


As in the other thread: which relationships apply here ?

The Attempt at a Solution


So I've defined my {Bn} already and proven that it is a sequence of mutually exclusive events in script A. I need to prove that U Bi (i=1 to infinity) is equal to U Ai (i=1 to infinity) to use the Countable Additivity formula.

My prof states that I need to prove the 2nd property of Countable Additivity by Induction but I'm not really sure how to go about.
Induction is something like:
proving a claim is true for n=1​
PLUS
proving that: IF it's true for n THEN it's true for n+1​
 
Sai Alonzo said:

Homework Statement


Prove the continuity from below theorem. If {An} is a monotone nondecreasing sequence of events in A and lim An is in A (n-->infinity) then
the probability of the countable union of An = probability of the lim An, n--> infinity = lim P(An), n--> infinity

Homework Equations


Assumptions
A1 is a subset of A2 which is a subset of A3 and so on.. (monotone nondecreasing sequence)
{An} is in A
lim An is in A, n--> infinity

The Attempt at a Solution


So I've defined my {Bn} already and proven that it is a sequence of mutually exclusive events in script A.
I need to prove that U Bi (i=1 to infinity) is equal to U Ai (i=1 to infinity) to use the Countable Additivity formula.

My prof states that I need to prove the 2nd property of Countable Additivity by Induction but I'm not really sure how to go about.
 
Well, I don't really feel qualified for the contents of the statements, but: do you recognize what I wrote in #2 about the method of induction ?
 
BvU said:
Well, I don't really feel qualified for the contents of the statements, but: do you recognize what I wrote in #2 about the method of induction ?

Yes I understand the concept of induction but more like I don't know how to begin or what to begin the proof with?
 
I suggest you post this question again in a new thread, this time with a complete description in sections 1, 2 and 3. E.g. what Bn are you talking about? And could you cite the theorem? And under point 3, what is your attempt to formulate the induction hypothesis?

This thread so far is a mess and hard to read, i.e. to figure out what it is actually about.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K