Proving the Convolution Theorem for Laplace Transform

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Discussion Overview

The discussion revolves around the relationship between the Laplace transforms of functions and their convolution, specifically questioning the validity of the convolution theorem in this context. Participants explore the implications of the theorem and seek proof related to the multiplication of Laplace transforms.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant states the convolution theorem for Laplace transforms as \(\mathcal{L}\{f(t)*g(t)\}=F(s)G(s)\), questioning the relationship between \(F(s)G(s)\) and \(f(t)g(t)\).
  • Another participant acknowledges the existence of a relation but refers to external material for clarification, specifically mentioning the 'multiplication' part under the 'Properties and theorems' section.
  • A participant challenges the previous claim by stating that the referenced material only discusses the convolution of original functions, not the multiplication of their transforms.
  • Further, a participant offers a snapshot of the material, indicating that the convolution is performed over a specific imaginary line.
  • Finally, a participant requests assistance in proving the relationship \(F(s)*G(s)=f(t)g(t)\), indicating a desire for a formal proof.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the relationship between the Laplace transforms and their convolution, with multiple viewpoints presented and no clear resolution on the proof requested.

Contextual Notes

Some participants express uncertainty regarding the specific conditions under which the convolution theorem applies, and there is mention of limitations in the referenced material that may affect the understanding of the theorem.

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\mathcal{L}\{f(t)*g(t)\}=F(s)G(s)

Is there some relation between

F(s)*G(s) and f(t)g(t)?

##*## is convolution.
 
Last edited:
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Any answer?
 
Yes, there is.

See here. Check out the 'multiplication' part under the 'Properties and theorems' section.
 
Sorry but I see here only convolution of originals.
 
Here, let me help you, I've taken a snapshot of it:

4RHiQ.png


The convolution is being done over an imaginary line Re{(\sigma)} = c
 
Ok. Tnx. Do you know how to prove?

##F(s)*G(s)=f(t)g(t)##?
 

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