Proving the Equation (y-2)/(2-y)=-1 for All Real Numbers y ≠ 2

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SUMMARY

The equation (y-2)/(2-y) = -1 holds true for all real numbers y ≠ 2. The proof involves manipulating the expression by multiplying both the numerator and denominator by the conjugate of the denominator, leading to the simplification that confirms the equality. The final result is derived through algebraic manipulation, demonstrating that (y-2) = -1(2-y) simplifies to (y-2) = (y-2). This confirms the equation's validity across the specified domain.

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mike_302
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This is not a very difficult question, by any means, and I see that the answer does equal -1, but I do not see the mathematical steps that go on to prove that (y-2)/(2-y)=-1 .. Can someone show me the steps that go through that? Thanks in advance.
 
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Dude...

1) (y-2)/(2-y)=-1
2) (y-2)=-1(-y+2)
3) (y-2)=(y-2)

Wait a bit and I'll post the same in TeX.
 
Better way.

\frac{y-2}{2-y}=\frac{(y-2)(y+2)}{(2-y)(2+y)}=\frac{y^2-4}{4-y^2}=-1
 
lol, ok sorry. That was posted slightly incorrectly the first time. Basically, the textbook says "simplify: (y-2)/(2-y) " and the back of the book gives the final answer to be -1, so I can't do the left side right side stuff
 
ahh, yes, I see your second post now . That does seem to be better. Thanks
 
so basically what I do in your second post is I multiply the bottom and top by the conjugate of the denominator?
 
mike_302 said:
so basically what I do in your second post is I multiply the bottom and top by the conjugate of the denominator?
Yes. (I had to look up what's a conjugate to answer your question.:shy:)

In the future, could you please post your homework/assignment questions in the homhttps://www.physicsforums.com/forumdisplay.php?f=152"um?


This forum is more about theoretical discussions.
 
Last edited by a moderator:
Wow, I'm stupid...

\frac{y-2}{2-y}=\frac{-1(2-y)}{2-y} =-1

This is what you get for not doing any maths for almost a year.
 
OH! Jeeeze. I see, lol, Thanks. and, yes. Normally I post in the math homework forums but I think I just clicked on the wrong link and got here. I didn't notice that, sorry.
 
  • #10
ivanetski said:
This forum is more about theoretical discussions.

I thought it was about general math.
 
  • #11
(y-2)/(2-y) = -1 is an equation

(y-2)/(2-y) is not an equation; it's an expression.
 
  • #12
mike_302 said:
and the back of the book gives the final answer to be -1, so I can't do the left side right side stuff

It's -1 for all real numbers y not equal to 2. :wink:
 

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