Proving the Inductive Relationship for the Gamma Function

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The discussion focuses on proving the inductive relationship for the Gamma function, specifically that gamma(v+1)(v+1)(v+2)...(v+k)=gamma(v+k+1) for k=1,2,3.... The initial proof attempts to establish a base case and an inductive hypothesis but encounters confusion regarding the application of the Gamma function's properties. The key relationship used is x*gamma(x)=gamma(x+1), which is crucial for the inductive step. A correction is made to the inductive hypothesis, clarifying that it should include the product up to k. The discussion emphasizes the importance of accurately applying the properties of the Gamma function to complete the proof.
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Homework Statement



Prove by induction that gamma(v+1)(v+1)(v+2)...(v+k)=gamma(v+k+1) for k=1,2,3...


Homework Equations



Really just using the relation x*gamma(x)=gamma(x+1)


The Attempt at a Solution



for a basis gamma(v+1)(v+1)=gamma(v+1+1)
so holds for k = 1

inductive hypothesis
gamma(v+1)(v+n)=gamma(v+n+1)

now for k = n+1 i get
gamma(v+1)(v+n+1)=gamma(v+n+2)

but what confuses me is if i use the above relationship, then gamma(v+n+2) should equal (v+n+1)*gamma(v+n+1), unfortunately my proof claims it's equal to gamma(v+1)(v+n+1). I'm lost at this step
 
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Your inductive hypothesis is wrong.

It should be gamma(v+1)(v+1)(v+2)...(v+k)=gamma(v+k+1) for some k.
Your inductive step then is gamma(v+1)(v+1)(v+2)...(v+k)(v+k+1)=gamma(v+k+2).
Alright?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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