Proving the Integral Formula for Powers of Sine for the Perplexed

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SUMMARY

The integral formula for powers of sine is established as follows: ∫sin^n x dx = -(1/n)cos x sin^(n-1) x + ((n-1)/n) ∫sin^(n-2) x dx. This formula is derived using the technique of integration by parts, specifically applying the product rule to sin(x) and sin^(n-1)(x). The discussion emphasizes the importance of understanding integration techniques to effectively prove this formula.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with integration by parts
  • Knowledge of trigonometric identities
  • Experience with recursive formulas in calculus
NEXT STEPS
  • Study the method of integration by parts in detail
  • Explore trigonometric identities and their applications in integration
  • Research recursive formulas in calculus for deeper insights
  • Practice solving integrals involving powers of trigonometric functions
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in advanced integration techniques will benefit from this discussion.

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I need help with a question and I'm totally stuck at this! My friends can't help me so you are my last way out!

Prove

∫sin^n x dx= -(1/n)cos x sin^n-1 x + ((n-1)/n) ∫sin^n-2 x dx

Thanks for your time!

Sincerely :)
 
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I see a product: \sin(x)\sin^{n-1}(x). Try partial integration on that...
 

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