Proving the Maximal Member in a Converging Sequence An > 0 to 0

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Homework Help Overview

The discussion revolves around proving that a bounded sequence \( A_n \) that converges to 0, with all terms being positive, contains a maximal member. Participants are exploring the implications of convergence and the properties of bounded sequences.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the characteristics of the sequence, noting that if it converges to 0, only finitely many terms can differ from 0. They question how to formally express these ideas mathematically and seek to clarify the conditions under which a maximal member exists.

Discussion Status

The discussion is ongoing, with participants attempting to combine their insights and formalize their reasoning using proper mathematical notation. There is an active exploration of the concepts involved, but no consensus has been reached yet.

Contextual Notes

Participants are considering the implications of the sequence being bounded and converging to 0, as well as the nature of its terms being positive. There is a focus on how to mathematically articulate these properties without providing a complete proof.

transgalactic
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An is a bounded sequence which converges to 0.
An>0 for every n.
prove that in this sequence we have a maximal member
??

again its obvious because if a sequence is descending and it converges from a positive number
to 0.
so 0 is the larger lower bound
and our first member must be the larger

how to transform it to math?
 
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If it converges to 0, then finitely many members of the sequence take on a different value (that number may be small or large but it is still finite) and the rest of the terms approach 0.
 
how to prove it mathematically?
 
By combining what you and I wrote and using proper notation
 

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