Proving the Midpoint Theorem for a Plane Quadrilateral | Helpful Tips

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The discussion focuses on proving the Midpoint Theorem for a plane quadrilateral ABCD, specifically analyzing the properties of the diagonals intersecting at point O and midpoints X and Y of diagonals AC and BD, respectively. Key equations derived include BA + BC = 2BX and BA + BC + DA + DC = 4YX, demonstrating relationships between the sides and midpoints. The participants emphasize the non-regularity of the quadrilateral due to differing lengths of sides and provide insights into vector relationships necessary for proof completion.

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Superdreamer
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Please Help! nasty vector question

The diagonals of a plane quadrilateral ABCD intersect at O,and X,Y are the midpoints of the diagonals AC,BD respectively.Show that
The shape is not regular the top and bottom are different lengths as can be the sides

1) BA + BC= 2BX
Got this part by proving
BA=BX+XA
BC=BX+XC
BA+BC=BX+XA+BX+XC
2BX+XA+XC
2BX-1/2AC+1/2AC=BA+BC
From here on in I just go blank
I've tried proving no 2 by getting DA=DX+XA OR DY+YA etc but it ain't working

2) BA + BC +DA + DC=4YX
3) 2AB +_2BC +2CA=0
iF 0A+OB+OC+OD=4OM find location of M

Thanks in advance
 
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Perhaps it would help to consider that

YX=YA+AX
YX=YB+BX
YX=YC+CX
YX=YD+DX

their sum is

4YX=AX+BX+CX+DX+YA+YB+YC+YD

since AX+CX=0 and YB+YD=0, we have

4YX=BX+DX+YA+YC
 
Last edited:

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