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I am trying to prove that the poisson distribution is normalized, I think I've got an ok start but just having trouble with the next step.
A counting experiment where the probability of observing n events (0≤n<∞) is given by:
P(n) = (μ^n)/n! * e^(-μ)
Where μ is a real number.
Background (possibly incorrect)
So it's discrete, as n will take integer values; I need a sum not an integral.
Ʃ P(n) from n=0 to ∞ is just given by:
Ʃ (μ^n)/n! * e^(-μ)
And e^(-μ) does not vary with n, so:
Ʃ P(n) = e^(-μ) * Ʃ (μ^n)/n!
Important bit
Now as I am trying to prove it is normalized, i need to get Ʃ P(n) = 1, so I assume my problem is getting from:
(μ^n) / n!
to
e^μ
Any tips or help would be much appreciated, thanks in advance.
Homework Statement
I am trying to prove that the poisson distribution is normalized, I think I've got an ok start but just having trouble with the next step.
Homework Equations
A counting experiment where the probability of observing n events (0≤n<∞) is given by:
P(n) = (μ^n)/n! * e^(-μ)
Where μ is a real number.
The Attempt at a Solution
Background (possibly incorrect)
So it's discrete, as n will take integer values; I need a sum not an integral.
Ʃ P(n) from n=0 to ∞ is just given by:
Ʃ (μ^n)/n! * e^(-μ)
And e^(-μ) does not vary with n, so:
Ʃ P(n) = e^(-μ) * Ʃ (μ^n)/n!
Important bit
Now as I am trying to prove it is normalized, i need to get Ʃ P(n) = 1, so I assume my problem is getting from:
(μ^n) / n!
to
e^μ
Any tips or help would be much appreciated, thanks in advance.
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