Proving the second fundamental theorem of calculus?

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SUMMARY

The discussion focuses on proving the second fundamental theorem of calculus, specifically demonstrating that the derivative of the integral of a function f(u) from a to x equals f(x). The hint provided suggests using Taylor expansion of f(u) around x to facilitate the proof. Participants clarify that the integral is a function of x, not u, which is crucial for correctly applying differentiation. The confusion arises from the inclusion of the constant term F(a) in the derivative calculation, which should not be present in the final result.

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Vitani11
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Homework Statement


Show that Dx∫f(u)du = f(x) Where the integral is evaluated from a to x. (Hint: Do Taylor expansion of f(u) around x).

Homework Equations


None

The Attempt at a Solution


I have

... = Dx(F(u)+C) = Dx(F(x-a)+C) = dxF(x) - dxF(a) = f(x)-f(a). My problem is that it should be only f(x), not f(x) - f(a). I did a taylor expansion of f(u) around x and I'm not sure how that is supposed to help me...
 
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I know that for an integral F(a) (where a is not a variable) the derivative of the integral would be 0, and that's why it would not be included in the final answer, but I don't know how to show that.
 
Vitani11 said:
Dx(F(u)+C)
You are starting with ##\int_a^xf(u)du##, so that is a function of x (or maybe of a and x). It is not a function of u.
 

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