Proving the Truth of \sum^{\infty}_{n=1}|x_{n}|=0

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Homework Help Overview

The discussion revolves around the proposition regarding the convergence of the series \(\sum^{\infty}_{n=1}|x_{n}|=0\) and its equivalence to the condition that all terms \(x_{n}\) are zero. Participants are exploring the implications of this proposition and seeking ways to prove it.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants attempt to prove both directions of the proposition, noting success with one direction but difficulty with the other. Questions arise regarding the interpretation of symbols and terms used in the proposition, as well as the validity of certain assumptions.

Discussion Status

Participants are actively engaging with the proposition, with some providing suggestions for proof strategies, such as proof by contradiction. There is ongoing clarification regarding terminology and notation, indicating a collaborative effort to understand the problem better.

Contextual Notes

There is mention of potential confusion over the notation used, particularly the symbol for equivalence (⇔) and the term "IN" which refers to natural numbers. Participants are also considering the implications of the series being equal to zero and its relationship to the individual terms \(x_{n}\).

fderingoz
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Homework Statement



Is the proposition

\sum^{\infty}_{n=1}|x_{n}|=0 ⇔\foralln\inIN x_{n}=0

true? If it is true how can we prove that ?

Homework Equations


The Attempt at a Solution


I proved the \Leftarrow side of proposition but i could not prove the \Rightarrow side of proposition.
 
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Is it not true that \sum_n |x_n| > x_m for all m?
 
fderingoz said:

Homework Statement



Is the proposition

\sum^{\infty}_{n=1}|x_{n}|=0 ⇔\foralln\inIN x_{n}=0

true?
Is this what you're trying to prove?
$$ \sum^{\infty}_{n=1}|x_{n}|= 0 \iff \forall n \in Z,~ x_{n} = 0$$

I wasn't sure what you meant by IN. Also, one symbol you used (⇔) renders as a box in my browser.
Edit: Now it's showing up. That's odd, it didn't before.

Tip: Use one pair of tex or itex tags for the whole expression, rather than a whole bunch of them.
fderingoz said:
If it is true how can we prove that ?

Homework Equations


The Attempt at a Solution


I proved the \Leftarrow side of proposition but i could not prove the \Rightarrow side of proposition.
 
Last edited:
Mark44

The proposition which i want to prove is exactly the proposition which you write. I meant natural numbers by IN. Thanks for your suggestions.

I am waiting for your answers.
 
fderingoz said:
Mark44

The proposition which i want to prove is exactly the proposition which you write. I meant natural numbers by IN. Thanks for your suggestions.

I am waiting for your answers.

Try a proof by contradiction. Assume one of the a's isn't zero.
 
\sum\limits_{n=1}^{\infty}|x_{n}|=0\Rightarrow\lim \limits_{n\rightarrow\infty}\sum\limits_{k=1}^{n}|x_{k}|=0. Since s_{n}= \sum\limits_{k=1}^{n}|x_{k}| is an increasing sequence it can converge only its supremum. So \sup\limits_{n}s_{n}=0. Thus \forall n,\, 0\leq s_{n} = \sum\limits_{k=1}^{n}|x_{k}|\leq 0 which means \forall n,\, x_{n}=0.

I made this proof. What do you think is there any mistake in this proof ?
 

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