Proving the weyl tensor is zero problem

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The discussion centers on proving that all Robertson-Walker models are conformally flat by demonstrating that the Weyl tensor is zero. The participant attempts to substitute values for the Ricci tensor and Ricci scalar into the Weyl tensor equation but encounters difficulties with the Riemann tensor being undefined. They are advised to refer to the definitions of the Riemann tensor and other related tensors, emphasizing the importance of deriving these forms independently for clarity. The conversation highlights the necessity of understanding the underlying mathematical structures to solve the problem effectively. Ultimately, the goal is to confirm the vanishing of the Weyl tensor for the models in question.
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Homework Statement


Show that all Robertson - Walker models are conformally flat.


Homework Equations


Robertson Walker Metric: ds^{2}=a^{2}(t)\left(\frac{dr^{2}}{1-Kr^{2}}+r^{2}(d\theta^{2}+(sin\theta)^{2}d\phi^{2} )\right)-dt^{2}

Ricci Tensor: R_{\alpha\beta}=2Kg_{\alpha\beta}

Ricci Scalar: R=8K

Weyl Tensor: C_{\alpha\beta\gamma\delta}=R_{\alpha\beta\gammaδ}-\frac{1}{2}(g_{\alpha\gamma}R_{\beta\delta}-g_{\alpha\delta}R_{\beta\gamma}-g_{\beta\gamma}R_{\alpha\delta}+g_{\beta\delta}R_{\alpha\gamma}) + \frac{R}{6}(g_{\alpha\gamma}g_{\beta\delta}-g_{\alpha\delta}g_{\beta\gamma})

The Attempt at a Solution


In order for the models to be conformally flat the weyl tensor must vanish, therefore that is what I have tried to show. By subbing in the values for the Ricci tensor and the Ricci scalar (both of which were given in a lecture by my professor) I arrived at the following expression:

C_{\alpha\beta\gammaδ}=R_{\alpha\beta\gamma\delta}-\frac{2}{3}K(g_{\alpha\gamma}g_{\beta\delta}-g_{\alpha\delta}g_{\beta\gamma})

However, as you can see I am left with the Riemann tensor undefined and I cannot show the weyl tensor to be zero. Any help is greatly appreciated, thanks!
 
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I'm pretty sure your textbook contains the definition of the Riemann tensor, and of the other tensors. Look it up. (You will only need to know the metric to calculate it.) Then, the Ricci tensor is related to the Riemann one through
R_{ij} = R^k_{\, ikj},
and, finally, the Ricci scalar is simply the trace of the Ricci tensor.

So well, I'd recommend you start working from the definitions. It is probably more instructive to derive those forms of the Ricci tensor and scalar yourself, and see if you get the same forms for this specific metric.
 
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