Proving Vector Space of U is Null Space of T

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SUMMARY

The discussion centers on proving that the null space of a linear transformation T, defined as T: U → V, is a vector space within U. The null space, or kernel, is explicitly defined as ker(T) = {u ∈ U : T(u) = 0}. To establish that this kernel is a subspace of U, one must demonstrate that it satisfies the three criteria for a subspace: it contains the zero vector, is closed under vector addition, and is closed under scalar multiplication.

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franky2727
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got a question show that the null space of T is a vector space of U given the mapping T:U->V

i know that null space or kernal of T is kerT={uEU: T(u)=0} and is a subset of U but don't have a clue where to start applying this to my question?
 
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Well, how do you show that a subset of U is a subspace of U?
 

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