Proving what the reaction force equals with moments in mechanics.

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SUMMARY

The discussion focuses on calculating the vertical reaction forces at brackets A and B for a horizontal piece of wood weighing 40N, supported by two brackets. The reaction force at A is initially 24N and at B is 16N. When an object with weight W is placed at a distance x from point C, the vertical reaction force at A can be expressed as (24 - W(x - 1.4))N. The moment equation used is Moment = Force x Distance, and the superposition principle is applied to determine the additional reaction force at A due to the weight W.

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xllx
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Homework Statement


A horizontal piece of wood that has a weight 40N is held in equilibrium by two brackets, A and B. The wood is 1.6m long (CD). A is 0.4m from C and B is 0.2m from D. Meaning that there is 1.0m between A and B. At rest the reaction force at A is 24 N and at B 16N. When an object is put on the wood at xm from C, show that the vertical reaction force on the shelf at A is (24-W(x-1.4))N


Homework Equations


Moment=Force x Distance


The Attempt at a Solution


I understand that the W(x-1.4) is the moment of the object but I can't seem to get the 24.
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right

Any help at all would be greatly appreciated. many thanks.
 
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xllx said:

Homework Statement


A horizontal piece of wood that has a weight 40N is held in equilibrium by two brackets, A and B. The wood is 1.6m long (CD). A is 0.4m from C and B is 0.2m from D. Meaning that there is 1.0m between A and B. At rest the reaction force at A is 24 N and at B 16N. When an object is put on the wood at xm from C, show that the vertical reaction force on the shelf at A is (24-W(x-1.4))N


Homework Equations


Moment=Force x Distance


The Attempt at a Solution


I understand that the W(x-1.4) is the moment of the object but I can't seem to get the 24.
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right

Any help at all would be greatly appreciated. many thanks.
The 24 N force at A is the reaction force before the object W is placed on the plank. It is given to you (or it could be calculated). By the superposition principle, the additional reaction at A as caused by W acting alone , is added to the existing 24N reaction at A.

EDIT:
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right
If you wish to start from scratch, it's
(1.4 -x)W -A(1) + 40(.6) =0
Solve for A. You have to watch your plus and minus signs (counterclockwise vs. clockwise moments) when summing moments about a point.
 
Last edited:

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