Pulley and Mass: How to Calculate Velocity?

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SUMMARY

The discussion focuses on calculating the velocity of point C in a double pulley system, utilizing the relationship between angular velocity and radius. The key equation is v = w * r, where v is the linear velocity, w is the angular velocity, and r is the radius of the pulleys. The user proposes that the velocity of C can be expressed as v = w * r_b - w * r_a, depending on the unwinding of cables from each pulley. The conversation emphasizes the importance of visualizing the mechanics through practical experimentation with strings and pulleys.

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  • Understanding of angular velocity and linear velocity relationships
  • Familiarity with pulley systems and their mechanics
  • Basic knowledge of algebraic manipulation of equations
  • Experience with practical physics experiments involving pulleys
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Homework Statement



See attached image.

I'm wondering how one would express the velocity of C with respect to the angular velocity of the pulleys and the radii.

Homework Equations



v=w*r

The Attempt at a Solution


I've never quite done double pulleys such as these. Usually, If i had a single object attached, using one cable, to the edge of a pulley, its velocity would be 'v=wr' where 'r' is the radii of the pulley where the cable lies. But how about this case?

PS. This is not an assignment. It's merely a question I came across reading my book.
 

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Hint: As the double pulley turns, the cable unwinds from each pulley at the same speed as the tangential speed of the rim. Hint2: If the cable is lengthens by a amount L, how far does the lower pulley drop?
 
Tell me if this is right:
If the right cable unwinds at v=w*r_b and the left cable at v=w*r_a, then c moves at v = w*r_b - w*r_a
 
the_dialogue said:
Tell me if this is right:
If the right cable unwinds at v=w*r_b and the left cable at v=w*r_a, then c moves at v = w*r_b - w*r_a
What if r_a = r_b? Would your answer make sense then?
 
Indeed it would not.

In that case I'm stuck!
 
Anyone?
------
 
the_dialogue said:
Tell me if this is right:
If the right cable unwinds at v=w*r_b and the left cable at v=w*r_a, then c moves at v = w*r_b - w*r_a

I think you should consider that v is a linear function of r_a and r_b, so v = u1.r_a + u2.r_b. Now, consider first r_a = 0 which allows you to determine the coefficient u2. Next, put r_b = 0, which allows you to find u1. This should give you the overall expression ; check it for a specific case...
 
I recommend that you play around with a piece of string until you figure it out. If you don't have a pulley handy, wrap the string around a tin can and unwind it. This will help you visual what's going on and figure out how the lengthening of the string relates to the turning of the pulley. Treat the double pulley as two single pulleys of different radii (since that's what they are!).

You can also use this method to figure out how the position of C depends on the length of hanging chain. If the string lengthens by 4 inches, how far does C fall?

Review the hints I gave in post #2.
 

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