Calculate the initial acceleration of this pulley system

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
8 replies · 3K views
Phantoful
Messages
30
Reaction score
3

Homework Statement


w1Gfx7r.png


Homework Equations


W=mg
F=ma

The Attempt at a Solution


I'm not sure how I should be answering this problem, and the diagram itself looks odd. I was thinking about how it would work in real life, since the biggest pulley is attached to the leftmost pulley, by the same string that m1 is on, wouldn't acceleration all be zero? Since the biggest pulley is attached to the roof...

Also, looking at it from FBD, The masses seem simple (m1*g, T1 and m2*g, T2) but when I try to do the pulleys, it's like a recursion happens because the whole system loops.
 

Attachments

  • w1Gfx7r.png
    w1Gfx7r.png
    7 KB · Views: 1,322
Physics news on Phys.org
Chestermiller said:
The force balance on the left massless pulley, has a force of T upwards and 2T downwards.
Not only that, but a net force acting on a massless pulley doesn't get you any closer to determining its acceleration. It seems like force balance equations will not work for this problem.
Here is another way to look at it. Since the pulley on the left is massless, it will move either up or down to compensate for the motions of ##m_1## and ##m_2## without any opposing or assisting force at all. Are the motions of the two masses affected by any force other than gravity?
 
tnich said:
Not only that, but a net force acting on a massless pulley doesn't get you any closer to determining its acceleration. It seems like force balance equations will not work for this problem.
Here is another way to look at it. Since the pulley on the left is massless, it will move either up or down to compensate for the motions of ##m_1## and ##m_2## without any opposing or assisting force at all. Are the motions of the two masses affected by any force other than gravity?
no. If the tension in the rope is zero, the acceleration of each mass is g.
 
Chestermiller said:
no. If the tension in the rope is zero, the acceleration of each mass is g.
Sounds like you have just solved the problem.