Pulley Tension and Normal Force: Understanding the Relationship

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SUMMARY

The relationship between pulley tension and normal force is defined by the principle that the normal force exerted by the surface on a massless pulley is twice the tension in the string. This is due to the fact that two objects tied to either end of the string exert equal tension, resulting in a downward force on the pulley that is countered by the normal force. When calculating the acceleration of the system, it is crucial to consider the effective mass as 2T/g, where T is the tension and g is the acceleration due to gravity, to arrive at accurate results.

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  • Understanding of Newton's laws of motion
  • Basic knowledge of tension in strings
  • Familiarity with the concept of normal force
  • Comprehension of massless pulley systems
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When two objects are tied to some two ends of a string on a pulley hung on a surface, the normal force applied by the surface on the pulley is twice the tension of the string. Why is this so?
In fact one of the questions had such a pulley hung on a pulley with the help of a string whose other end is tied to a object. The question was to find the acceleration of all the three objects and I found the relative (to pulley) acceleration of first two objects. Now this pulley was given to be massless. So I thought the mass on this side should be taken as the sum of the two masses tied while finding the acceleration of pulley. This resulted in approaching a wrong answer. However when the mass was taken to be 2T/g where t is the tension on the string and g is the acceleration due to gravity my answer was perfect. I didn't understand the concept behind this. I mean what about those masses
 
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vaishakh said:
When two objects are tied to some two ends of a string on a pulley hung on a surface, the normal force applied by the surface on the pulley is twice the tension of the string. Why is this so?
The strings are pulling the pulley down with a force with contributions from each string. But since the pulley is not accelerating downward, there must be a compensating force of the same magnitude and opposite direction coming from the place where it is hung.
 
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