- #1

- 1,456

- 44

However, say we have ##\sqrt{-5}##. In order to simplify this, we do the following: ##\sqrt{-5} = \sqrt{(-1)(5)} = \sqrt{-1}\sqrt{5} = i\sqrt{5}##. Why is this a valid manipulation given the previous statement that ##\sqrt{a}\sqrt{b} = \sqrt{ab}## is invalid when ##a, b< 0##?