Pulse duration from interferometric autocorrelation

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Voxynn
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Hi,

I have some interferometric autocorrelation traces of ~20fs pulses. Does anyone know how to convert to or calculate the actual pulse duration from the fringes of the trace?

Thanks,

Richard
 
Are your pulses Gaussian, Sech, or Lorentzian?

Use the pulse type to figure out the time bandwidth product [tex]\delta t \delta \omega[/tex]. The spectrum tells you [tex]\delta \omega[/tex]. For example, a Gaussian has [tex]\delta t \delta \omega = \frac{2 \log 2}{\pi}[/tex].
Use this equation to solve for [tex]\delta t[/tex]
 
Woah sorry. [tex]\delta t \delta \omega[/tex] is [tex]4 \log 2[/tex]. What I quoted was [tex]\delta t \delta \nu[/tex]. In case you wonder, [tex]\nu[/tex] is ordinary frequency in hertz and [tex]\omega[/tex] is angular frequency.
 
My pulse is gaussian (or near enough). I know how to calculate time/bandwidth product for actual spectra (wavelength vs intensity etc) but how can I extract similar info from the autocorrelation trace? I've attached a picture of the trace I have.
 
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  • Interferometric autocorrelation trace: a central intensity envelope with fast fringes, peaking near 0.26 at about -0.007 on the horizontal axis, falling to a baseline near 0.055 on either side, axes from -0.025 to 0.01 and 0 to about 0.25.
    autocorrelation.jpg
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The data is taken from an oscilloscope, so the units are time and voltage (intensity).