(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A horizontal 25 N pushing force acts on a 10 kg crate moving up a ramp. The ramp is inclined at 37 degrees above the horizontal.

How much work is done by this force in moving the crate a distance of 15m along the ramp?

2. Relevant equations

W = Fd

3. The attempt at a solution

This was on a previous test i took and i got it wrong and now looking over it again i cannot seem to figure it out.

I thought i could take the component of the pushing force parallel to the ramp and subtract the component of the weight of the block that is parallel to the ramp then just multiply that by the distance but that didnt work out to well.

here is was i did

The component of the pushing force parallel to the ramp is

25cos(37) = 19.96

the component of the weight parallel to the ramp (and opposite in direction of the component of the pushing force parallel to the ramp) is

mgsin(37)

10(9.8m/s^2)sin(37) = 58.9

so subtract those two

19.9 - 58.9 = - 39N

so W = 39N(15m)

W = 585 J

the correct answer is 300 J

Any help would be great.

Thank you :)

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Pushing a box up a ramp a certain distance - work

**Physics Forums | Science Articles, Homework Help, Discussion**