Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Qestion about pressure transducer

  1. Dec 20, 2011 #1
    i have to install a pressure transducer to convert the pressure value to volume, but its not the problem, the shape of the water tank , the water tank like cylinder but the base is concave to the bottom, how can i do that ? please
    thank you all
  2. jcsd
  3. Dec 20, 2011 #2
    A diagram with dimensions would be helpful. Try to solve the problem so we can see where to help.
  4. Dec 21, 2011 #3
    First, thank you for reply
    i want to measure the volume of water in the tank by using TECSIS pressure transducer with built in microcontroller and analoge output from it between 4-20mA , by using this equation P=g*h*density, i can get analoge output which indicate the volume, of course after set the microcontroller ,but the shape of the tank like cylinder and concave to the bottom-see the attachment-this means that i have two equation of the volume, what can i use with the transducer to solve this problem???

    Attached Files:

  5. Dec 21, 2011 #4
    I would refresh your memory regarding applications of triple integrals in calculus. You have a shape that looks like a hemisphere, you are trying to find its volume bounded by a plane at different heights measured from the bottom of the hemisphere. My "Mathematical handbook of Formulas and Tables" shows the volume of a Spherical cap of Radius r and Height h to be:


    The volume of a Right Circular cylinder of radius r and Height h is:


    You have two equations for Volume vs height, one for the sphere and another for the cylinder
  6. Dec 22, 2011 #5
    you are extremly right, but for example when the pressure equal 2 bar the output current will be 6 mA,
    from this equation P=density*h*g i can get P=density*g*(volume/Pi*r^2) this is for cylinder
    so i can set the microcontroller in the transducer to give me indication of volume instead of current
    P= 1000*9.8*(volume/Pi*r^2).................for pure water so the volume = p*(pi*r^2)/1000*9.8
    for 1m reduis
    volume = p*3.14/1000*9.8.......when pressure=2 bar
    volume = 64 m^3, and the transdcucer should give me 6mA but i can set the microcontroler
    (proportional control) to give me for example 0.64
  7. Dec 22, 2011 #6
    this is all equation for cylinder, but there is a spherical cap shap as u said , is there any method to switch the transducer and separate the volume indication between this two shapes ..i hope u get it other wise i would have a mistake in my delivery ..thank you
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook