Qestion about pressure transducer

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Homework Help Overview

The discussion revolves around the installation of a pressure transducer to measure the volume of water in a uniquely shaped tank, which is cylindrical with a concave base. Participants are exploring how to accurately convert pressure readings to volume given the tank's geometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the use of pressure equations to derive volume, considering the tank's shape. There are mentions of using a microcontroller to interpret the transducer's output and questions about how to handle the different volume equations for the cylindrical and concave shapes.

Discussion Status

Some participants have provided equations related to the volume of the tank's shapes and are questioning how to integrate these into the transducer's output. There is an ongoing exploration of methods to differentiate between the volume indications for the cylindrical and spherical cap shapes.

Contextual Notes

Participants note the complexity introduced by the tank's concave base and the need for precise measurements. There is an emphasis on ensuring the microcontroller is set correctly to reflect volume rather than just current output from the transducer.

fatima_ib89
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i have to install a pressure transducer to convert the pressure value to volume, but its not the problem, the shape of the water tank , the water tank like cylinder but the base is concave to the bottom, how can i do that ? please
thank you all
 
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A diagram with dimensions would be helpful. Try to solve the problem so we can see where to help.
 
First, thank you for reply
i want to measure the volume of water in the tank by using TECSIS pressure transducer with built in microcontroller and analoge output from it between 4-20mA , by using this equation P=g*h*density, i can get analoge output which indicate the volume, of course after set the microcontroller ,but the shape of the tank like cylinder and concave to the bottom-see the attachment-this means that i have two equation of the volume, what can i use with the transducer to solve this problem?
 

Attachments

I would refresh your memory regarding applications of triple integrals in calculus. You have a shape that looks like a hemisphere, you are trying to find its volume bounded by a plane at different heights measured from the bottom of the hemisphere. My "Mathematical handbook of Formulas and Tables" shows the volume of a Spherical cap of Radius r and Height h to be:

V=1/3*pi*h^2(3r-h)

The volume of a Right Circular cylinder of radius r and Height h is:

V=pi*r^2*h

You have two equations for Volume vs height, one for the sphere and another for the cylinder
 
you are extremely right, but for example when the pressure equal 2 bar the output current will be 6 mA,
from this equation P=density*h*g i can get P=density*g*(volume/Pi*r^2) this is for cylinder
so i can set the microcontroller in the transducer to give me indication of volume instead of current
ex:
P= 1000*9.8*(volume/Pi*r^2)....for pure water so the volume = p*(pi*r^2)/1000*9.8
for 1m reduis
volume = p*3.14/1000*9.8...when pressure=2 bar
volume = 64 m^3, and the transdcucer should give me 6mA but i can set the microcontroler
(proportional control) to give me for example 0.64
 
continue...
this is all equation for cylinder, but there is a spherical cap shap as u said , is there any method to switch the transducer and separate the volume indication between this two shapes ..i hope u get it other wise i would have a mistake in my delivery ..thank you
 

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