[QM] Two-Particle Systems: overlapping/non-overlapping wavefunctions

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SUMMARY

This discussion focuses on the concept of overlapping and non-overlapping wavefunctions in quantum mechanics, specifically referencing Griffiths' text on exchange forces. The integral expressions for expectation values, such as $$\langle x \rangle_{ab}$$ and $$\langle x \rangle_{ba}$$, highlight the importance of wavefunction overlap in determining particle interactions. It is established that if two wavefunctions, $$\psi_a$$ and $$\psi_b$$, do not overlap, the expectation values vanish, allowing for the assumption that such particles can be treated as distinguishable. The discussion clarifies that overlap implies both particles occupying the same position, $$x_1 = x_2$$.

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WeiShan Ng
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Homework Statement


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Hi, I was reading Griffiths and stumble upon some questions. This is from 5.1.2 Exchange Forces. The section is trying to work out the square of the separation distance between two particles, $$\langle (x_1 - x_2)^2 \rangle = \langle x_1^2 \rangle + \langle x_2^2 \rangle - 2 \langle x_1 x_2 \rangle$$
My confusion came when
$$\int x_1 \psi_a (x_1)^* \psi_b (x_1) dx_1 \, \int x_2 \psi_b(x_2)^* \psi_a(x_2) dx_2 = \langle x \rangle _{ab} \langle x \rangle _{ba}$$ I don't get why there are ##\langle x \rangle _{ab}## and ##\langle x \rangle _{ba}## here , won't the $$\int x_2 \psi_b(x_2)^* \psi_a(x_2) dx_2=\int x_1 \psi_a (x_1)^* \psi_b (x_1) dx_1=0??$$ since both ##\psi_a## and ##\psi_b## are orthogonal to each other?

And in the next paragraph the text says
Notice that ##\langle x \rangle _{ab} ## vanishes unless the two wavefunctions actually overlap [if ##\psi_a(x)## is zero wherever ##\psi_b(x)## is nonzero, the integral in Equation 5.20 is zero] So if ##\psi_a## represents an electron in an atom in Chicago, and ##\psi_b## represents an electron in an atom in Seattle, it's not going to make any difference whether you antisymmetrize the wave function or not. As a practical matter, therefore, it's okay to pretend that electrons with nonoverlapping wave functions are distinguishable.
What is the meaning of "overlap" here? Based on the text given I assume it means both particles are "at the same position", i.e. ##x_1=x_2##. And how does an overlapping and non-overlapping wavefunction look like?

Homework Equations

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This picture may answer your question "how does an overlapping and non-overlapping wavefunction look like?"
 

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Nguyen Son said:
This picture may answer your question "how does an overlapping and non-overlapping wavefunction look like?"
Thank you!
 

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