# Quantization of energy in blackbody radiation

1. Sep 23, 2012

### limey

I have been reading alot of stuff on blackbody radiation and the ultraviolet catastrophe.
Here is what I have so far.

The ultraviolet catastrophe arises from the classical electrodynamics predicting an infinite amount of energy from a blackbody having any temperature.

As far as I have understood, the way that people imagined how a blackbody absorbed and emitted radiation, were modeled by oscillators in the surface of the blackbody that could absorb (and emit) any incoming EM radiation. (I think today we would call these oscillators electrons?).

Now, the result of this directly led to the ultraviolet catastrophe (the steps I have yet to fully understand). With Planck's introduction quantized energy, the problem was eventually solved.

But here is where it breaks down in my head. As I understand it, the "real" quantization is caused by the fact that the EM radiation can only be absorbed/emitting in energy packets corresponding to the energy levels of the atoms/electrons. However, does this not clash with the definition of a blackbody, i.e. a body capable of absorbing/emitting all wavelengths?

2. Sep 23, 2012

### Drakkith

Staff Emeritus
It's important to understand that the energy of each photon increases as wavelength decreases. This means that higher frequency photons have MORE energy than lower frequency ones. This is ultimately what resolved the UV catastrophe.

As for black body radiation, the key is that electronic transitions, IE electrons moving between energy states in an atom, are not the only way to emit EM radiation. Any electrical charge that is accelerated will emit radiation with a certain spread of frequencies. In a solid, liquid, or compressed gas the atoms and molecules vibrate and move around enough so that this spread of frequencies corresponds to the observed range we see when we look at hot objects. Such as a light bulb. The higher the temperature, the higher the average energy of each particle, and the higher the range of frequencies emitted is.

http://en.wikipedia.org/wiki/Thermal_motion

3. Sep 23, 2012

### Andy Resnick

Not exactly- the quantization step comes in by noting that only certain wavelengths can stably exist in a reflective cavity- an integer number of wavelengths must span the distance, or that particular wavelength can't stably exist in the cavity. This information is generally recast as a 'density of states', which is the number of stable radiation modes within a wavelength (or frequency) increment. This is what leads to the final result.

4. Sep 26, 2012

### limey

Thanks for the answers. It changes my perception quite a lot with the thermal radiation.