Quantum Mechanics - Quick integral probability question

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SUMMARY

The discussion focuses on the calculation of probability density in quantum mechanics, specifically regarding the hydrogen atom's electron energy levels. The probability of finding the electron within a volume element is expressed as ψψ*r²sinθdθd∅, where ψ represents the wavefunction. The confusion arises from the absence of the radial component dr in the first integral and the lack of integral limits for dr in the second integral, which should include the radial limits to accurately represent the volume element in spherical coordinates.

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  • Understanding of quantum mechanics principles, particularly wavefunctions.
  • Familiarity with spherical coordinates in three-dimensional space.
  • Knowledge of integral calculus, specifically multiple integrals.
  • Basic concepts of probability density in quantum systems.
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Students and professionals in physics, particularly those studying quantum mechanics, as well as educators looking to clarify concepts related to wavefunctions and probability densities in atomic systems.

binbagsss
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Okay so my book says (the context is electron hydrogen energy levels) the probability of finding the electron within dv=dv(r,∅,θ) is :

ψψ*r^2sinθdθd∅ [1]

where ψ is the wavefunction

And to find within dr of r is : ∫∫ψψ*r^2sinθdrdθd∅,[2] where the inner integral ranges over 0 to PI and the outter from 0 to 2PI

I don't really understand this. Why doesn't the first integral [1] for dv not require dr? As isn't the volume element given by r^2sinθdrdθd∅?

I also don't really understand why we don't need to include some integral limits corresponding to dr in [2]

If anyone can help explain things this would be greatly appreciated . Ta in advance !
 
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Looks like a typo to me.
 

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