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Quantum Mechanics - Quick integral probability question

  1. Nov 18, 2013 #1
    Okay so my book says (the context is electron hydrogen energy levels) the probability of finding the electron within dv=dv(r,∅,θ) is :

    ψψ*r^2sinθdθd∅ [1]

    where ψ is the wavefunction

    And to find within dr of r is : ∫∫ψψ*r^2sinθdrdθd∅,[2] where the inner integral ranges over 0 to PI and the outter from 0 to 2PI

    I don't really understand this. Why doesn't the first integral [1] for dv not require dr? As isnt the volume element given by r^2sinθdrdθd∅?

    I also dont really understand why we don't need to include some integral limits corresponding to dr in [2]

    If anyone can help explain things this would be greatly appreciated . Ta in advance !!
     
  2. jcsd
  3. Nov 18, 2013 #2

    Simon Bridge

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    Looks like a typo to me.
     
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