Quantum numbers for 4p² and 6s² electrons

[mathzeroh]

Good evening scholars! i just had a couple of questions about QNs.

ok so the problem says:

Give the sets of {n, l, m, s} for the electrons in:
a) $$4p^2$$
b) $$6s^2$$

i just want to see if I'm on the right track. here's what i put for the first one (a):

n= 4
l= 1
m= -1, 0
s= +/- 1/2

thanks!

 

[stunner5000pt]

Keep in mind that m is from -L TO +L
m would be -1, 0 , and +1
your spin is fine

what about the $6s^2$
so obvious n =6,
p = ?? for the s shell what is the P value?
and thus what is the m value and s values correspondingly?

 

[mathzeroh]

true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me?

as for the $$6^2$$, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-

 

[stunner5000pt]

true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me?

as for the $$6^2$$, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-

WHOOPS SORRY

my mistake, for the 4p2 you are correct the p orbital would be filled up for the -1 and 0 part
however, since you fill in the positive spins in first both the electrons have positive spin